Solve the system algebraically. 3x - 2y - 1 = 0 y = 5x 4 What is the solution?
3x - 2y - 1 = 0 y = 5x + 4 substitute y in the first equation the result is: 3x - 2(5x + 4) - 1 = 0 3x - 10x - 8 - 1 = 0 -7x - 9 = 0 -7x = 9 x = -9/7 y = 5(-9/7) + 4 = -45/7 + 4 = -45/7 + 28/7 = -17/7 The solution for the system 3x - 2y - 1 = 0 y = 5x + 4 is (-9/7, -17/7)
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Updated 9/29/2014 6:47:54 AM
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