The vertex from of the equation of a parabola is y=2(x+3)^2-5. What is the standard form of the equation?

y=2(x+3)^2-5 y=2(x^2+6x+9)-5 y=2x^2+12x+18-5 y=2x^2+12x+13 which is the standard form of the equation .

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Asked 11/25/2014 7:31:15 PM

Updated 11/29/2014 5:40:10 AM

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y=2(x+3)^2-5

y=2(x^2+6x+9)-5

y=2x^2+12x+18-5

y=2x^2+12x+13 which is the standard form of the equation .

y=2(x^2+6x+9)-5

y=2x^2+12x+18-5

y=2x^2+12x+13 which is the standard form of the equation .

Added 11/29/2014 5:40:10 AM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [11/29/2014 6:09:41 AM]

The vertex from of the equation of a parabola is y=7(x-3)2+4. . What is the standard form of the equation?

Question|Asked by ermajane

Updated 11/25/2014 9:46:58 PM

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**Weegy:** Establishing rules that will help you stay focused is called self-discipline. **User:** The vertex form of the equation of a parabola is y=4((x-2)squared-1.What is the standard form of the equation? (More)

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Updated 11/25/2014 9:57:26 PM

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