Question and answer
what is the equation of a circle whose center is at the origin and whose radius is 16?
Question
Asked 4/11/2013 12:08:13 PM
Updated 7/7/2014 1:20:56 AM
4 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [7/7/2014 1:17:29 AM]
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User: the legs of a right triangle have lengths of 4 and 5 units. what is the length of the hypotenuse ?

User: what is the length of the hypotenuse of a right triangle whose legs are 8 and 15 units in length ?

User: what is the length of the hypotenuse of an isosceles right triangle whose legs are 1 unit in length?

User: what is the equation of a circle whose center is at the origin and whose radius is 16?

Weegy: A. x^2 + y^2 = 3 B. x^2 + y^2 = 9 C. x^2 + y^2 = 81
ANGEEELICA|Points 7867|

User: which of the following points lies on the circle whose center is at the origin and whose radius is 10?

User: which of the following points lies on the circle whose center is at the origin and whose radius is 10? (square root of 10 , 0) (0, 2) (5, 5)

Question
Asked 4/11/2013 12:08:13 PM
Updated 7/7/2014 1:20:56 AM
4 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [7/7/2014 1:17:29 AM]
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Rating
3
The legs of a right triangle have lengths of 4 and 5 units. The length of the hypotenuse is: sqrt (4^2 + 5^2) = sqrt 41.
Added 7/7/2014 1:14:13 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [7/7/2014 1:19:09 AM]
3
The length of the hypotenuse of a right triangle whose legs are 8 and 15 units in length is: sqrt (8^2 + 15^2) = sqrt 289 = 17.
Added 7/7/2014 1:17:07 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [7/7/2014 1:19:42 AM]
3
The length of the hypotenuse of an isosceles right triangle whose legs are 1 unit in length is: sqrt (1^2 + 1^2) = sqrt 2.
Added 7/7/2014 1:19:03 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [7/7/2014 1:20:05 AM]
3
The equation of a circle whose center is at the origin and whose radius is 16 is x^2 + y^2 = 256.
Added 7/7/2014 1:20:56 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [7/7/2014 1:21:17 AM]
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Question
Expert Answered
Updated 5/25/2014 9:30:44 PM
10 Answers/Comments
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Added 5/25/2014 9:26:07 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [6/24/2014 11:54:08 AM]
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Added 5/25/2014 9:26:44 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [5/25/2014 9:36:43 PM]
m^4 - n^4
= (m^2 + n^2)(m^2 - n^2)
= (m^2 + n^2)(m + n)(m - n)
Added 5/25/2014 9:28:05 PM
This answer has been confirmed as correct and helpful.
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Added 5/25/2014 9:28:57 PM
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