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Calculate the # of sodium ions in 0.949 mol of sodium chloride. How many Na+ ions are there in 0.949 mol of NaCl?
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Asked 8/28/2010 6:31:35 PM
Updated 298 days ago|10/22/2023 9:30:28 AM
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User: Calculate the # of sodium ions in 0.949 mol of sodium chloride. How many Na+ ions are there in 0.949 mol of NaCl?

Weegy: 22
Expert answered|weesnar|Points 70|

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Asked 8/28/2010 6:31:35 PM
Updated 298 days ago|10/22/2023 9:30:28 AM
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Number of sodium ions = Number of chloride ions = 0.949 moles x 6.022 x 10²³ ions/mole
Number of sodium ions = 0.949 moles x 6.022 x 10²³ ions/mole 5.70 x 10²³ sodium ions
There are approximately 5.70 x 10²³ sodium ions in 0.949 moles of sodium chloride (NaCl).
Added 298 days ago|10/22/2023 9:30:28 AM
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Questions asked by the same visitor
% comp of SO4 in Na2SO4
Weegy: % comp of SO4 in Na2SO4 = 67.6% (More)
Question
Expert Answered
Updated 322 days ago|9/28/2023 2:42:37 PM
1 Answer/Comment
Solution:
1. Calculate the molar mass of SO4:
- Sulfur (S) has a molar mass of approximately 32.07 g/mol.
- Oxygen (O) has a molar mass of approximately 16.00 g/mol.
- Since there are four oxygen atoms in SO4, multiply the molar mass of oxygen by 4: 16.00 g/mol * 4 = 64.00 g/mol.
- Now, add the molar mass of sulfur and the molar mass of oxygen: 32.07 g/mol + 64.00 g/mol = 96.07 g/mol.

2. Calculate the molar mass of Na2SO4:
- Sodium (Na) has a molar mass of approximately 22.99 g/mol.
- Since there are two sodium atoms in Na2SO4, multiply the molar mass of sodium by 2: 22.99 g/mol * 2 = 45.98 g/mol.
- Add this to the molar mass of SO4 calculated earlier: 45.98 g/mol + 96.07 g/mol = 142.05 g/mol.

3. Calculate the percent composition of SO4 in Na2SO4:
- Divide the molar mass of SO4 (96.07 g/mol) by the molar mass of Na2SO4 (142.05 g/mol) and multiply by 100 to get the percentage: (96.07 g/mol / 142.05 g/mol) * 100 67.64%.

So, the percent composition of SO4 in Na2SO4 is approximately 67.64%.
Added 322 days ago|9/28/2023 2:42:37 PM
This answer has been confirmed as correct and helpful.
mass of 1.00 mol sodium
Weegy: Sodium has an atomic mass of 22.99. Therefore 1 mole of it weighs 22.99 grams. Similarly a mole of bromine weighs 79.9 grams. [ A mole of sodium bromide - NaBr - contains 1 mole each of sodium and bromine (note that this is not true for all chemical salts) and so 1 mole of it weighs 102.89 grams. ] (More)
Question
Expert Answered
Updated 7/20/2023 4:37:05 AM
2 Answers/Comments
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Added 7/20/2023 4:35:39 AM
This answer has been added to the Weegy Knowledgebase
Deleted by Bench_14 [7/20/2023 4:35:48 AM], Unflagged by Bench_14 [1/1/2024 8:34:02 AM], Flagged by Bench_14 [1/1/2024 8:34:30 AM], Deleted by Bench_14 [1/1/2024 8:34:31 AM]
Solution:
The molar mass of sodium (Na) is approximately 22.99 grams per mole (g/mol).

Therefore, the mass of 1.00 mole of sodium is:

1.00 mol x 22.99 g/mol 22.99 grams

So, the mass of 1.00 mole of sodium is approximately 22.99 grams.
Added 7/20/2023 4:37:05 AM
This answer has been confirmed as correct and helpful.
mass of 1.00 mol sulfur
Weegy: 1 mol S = 32.1 g S (More)
Question
Expert Answered
Updated 7/20/2023 4:36:14 AM
1 Answer/Comment
The molar mass of sulfur (S) is approximately 32.06 grams per mole (g/mol). This means that 1.00 mole of sulfur has a mass of approximately 32.06 grams.

Added 7/20/2023 4:36:14 AM
This answer has been confirmed as correct and helpful.
mass in grams of 1.35 mol Fe
Weegy: 75.4 g Fe (More)
Question
Expert Answered
Updated 7/20/2023 4:33:57 AM
1 Answer/Comment
Solution:
Now, you can calculate the mass of 1.35 moles of iron (Fe):

Mass (grams) = Number of moles × Molar mass
Mass (grams) = 1.35 mol × 55.845 g/mol
Mass (grams) 75.35675 grams

So, the mass of 1.35 moles of iron (Fe) is approximately 75.36 grams.
Added 7/20/2023 4:33:57 AM
This answer has been confirmed as correct and helpful.
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