Question and answer
Factor 3y2 - 4y.
Question
Asked 10/8/2012 12:11:50 PM
Updated 8/12/2014 11:43:25 PM
2 Answers/Comments
This answer has been confirmed as correct and helpful.
Flagged by yeswey [8/12/2014 11:29:52 PM], Edited by jeifunk [8/12/2014 11:43:02 PM], Edited by jeifunk [8/12/2014 11:43:16 PM], Unflagged by jeifunk [8/12/2014 11:43:25 PM], Confirmed by jeifunk [8/12/2014 11:43:25 PM]
s
Get an answer
Original conversation
User: Factor 3y2 - 4y.

Weegy:


User: Factor -4d3 + 28d2 - 4d.

Weegy: -4d3 + 28d2 - 4d. = -4d(d^2-7d+1)
OxTornado007|Points 5778|

User: 24a3b3c3 - 84a4b2c factored equals -12a3b2c(2bc2 + 7a). true or false

Weegy: True. 24a3b3c3 - 84a4b2c factored equals -12a3b2c(2bc2 + 7a).
LoveSolo|Points 80|

User: Factor -3x - 3y - 3z.

Weegy: -3x - 3y - 3z = -3(x + y + z)
sunny4691|Points 945|

User: Factor 10x3 + 8x2 - 6x.
Question
Asked 10/8/2012 12:11:50 PM
Updated 8/12/2014 11:43:25 PM
2 Answers/Comments
This answer has been confirmed as correct and helpful.
Flagged by yeswey [8/12/2014 11:29:52 PM], Edited by jeifunk [8/12/2014 11:43:02 PM], Edited by jeifunk [8/12/2014 11:43:16 PM], Unflagged by jeifunk [8/12/2014 11:43:25 PM], Confirmed by jeifunk [8/12/2014 11:43:25 PM]
New answers
Rating
3
3y^2 - 4y = y(3y - 4)
Added 8/12/2014 11:29:47 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [8/12/2014 11:40:23 PM]
3
10x^3 + 8x^2 - 6x = 2x(5x^2 + 4x - 3)
Added 8/12/2014 11:30:31 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [8/12/2014 11:40:43 PM]
Comments

There are no comments.

Add an answer or comment
Log in or sign up first.
Questions asked by the same visitor
Factor 16p4 - 24p3.
Weegy: First, recognize that this format follows that of a difference of two squares: a^2 - b^2. How would you factor this? (a + b)(a - b). [ (Try it: you get a^2 + ab - ab - b^2 = a^2 - b^2) So, what are the square roots of each of the terms above? sqrt of 16p^4 = 4p^2 and sqrt(625q^4) = 25q^2 So, you get (4p^2 - 25q^2)(4p^2 + 25q^2) You can't stop here, however, because you have another difference of two squares in the first term. The second term is not factorable without including imaginary numbers, so let's leave it as it is. Following the above procedure for 4p^2 - 25q^2, you get sqrt(4p^2) = 2p and sqrt(25q^2) = 5q So, 4p^2 - 25q^2 = (2p - 5q)(2p + 5q) Substituting this back, you get the final answer: 16p^4 - 625q^4 = (2p - 5q)(2p + 5q)(4p^2 + 25q^2) ] User: Factor x4y2 + x3y3 Weegy: monomial (More)
Question
Updated 6/13/2014 3:11:19 PM
2 Answers/Comments
16p^4 - 24p^3 = 8p^3(2p - 3)
Added 6/13/2014 3:10:41 PM
This answer has been confirmed as correct and helpful.
x^4y^2 + x^3y^3 = x^3y^3(x + y)
Added 6/13/2014 3:11:19 PM
This answer has been confirmed as correct and helpful.
32,006,665
questions answered
Popular Conversations
excretion rates of drugs vary greatly depending upon what
Weegy: Excretion rates of drugs vary greatly depending upon the type of drug involved and medical condition of the ...
8/1/2020 1:36:06 AM| 3 Answers
Which NIMS Management Characteristic helps to eliminate confusion ...
Weegy: The National Incident Management System (NIMS) is a standardized approach to incident management developed by ...
8/11/2020 1:55:28 PM| 3 Answers
GET
Answers.
GET THE APP.
weegy*
*
Get answers from Weegy and a team of really smart live experts.
S
L
P
L
P
Points 976 [Total 6999] Ratings 1 Comments 966 Invitations 0 Offline
S
L
Points 926 [Total 3923] Ratings 2 Comments 906 Invitations 0 Offline
S
L
P
R
P
R
L
P
P
C
R
P
R
L
P
R
Points 825 [Total 12916] Ratings 1 Comments 565 Invitations 25 Offline
S
L
P
1
Points 722 [Total 3578] Ratings 3 Comments 692 Invitations 0 Online
S
L
Points 413 [Total 1906] Ratings 1 Comments 403 Invitations 0 Online
S
L
Points 318 [Total 4702] Ratings 1 Comments 308 Invitations 0 Offline
S
L
1
Points 184 [Total 3495] Ratings 3 Comments 154 Invitations 0 Offline
S
L
Points 149 [Total 300] Ratings 4 Comments 109 Invitations 0 Online
S
L
L
Points 89 [Total 5377] Ratings 1 Comments 79 Invitations 0 Online
S
L
Points 85 [Total 244] Ratings 0 Comments 85 Invitations 0 Offline
* Excludes moderators and previous
winners (Include)
Home | Contact | Blog | About | Terms | Privacy | © Purple Inc.