A fluid of density 900 kg/m³ is at a depth of 6 m. Find pressure. (g = 9.8 m/s²)

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P = × g × h = 900 × 9.8 × 6 = 52,920 Pa = 52.9 kPa

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Asked 38 days ago|1/28/2026 6:36:13 AM

Updated 38 days ago|1/28/2026 6:56:01 AM

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cruz30

P = × g × h
= 900 × 9.8 × 6
= 52,920 Pa = 52.9 kPa

Added 38 days ago|1/28/2026 6:55:32 AM

This answer has been confirmed as correct and helpful.

Flora1988

P = 900 kg/m³ * 9.8 m/s² * 6 m = 52920 Pa.
Therefore, the pressure is 52920 Pascals or 52.92 kPa.

Added 38 days ago|1/28/2026 6:56:01 AM

This answer has been confirmed as correct and helpful.

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