suppose it take 3 days for a space vehicle to travel from earth to the moon. about how long would it take the same vehicle traveling at the same speed to reach venus? round to the nearest hundredth

Suppose it takes 3 days for a space vehicle to travel from earth to the moon. [ About how long would it take the same vehicle traveling at the same speed to reach Mercury?
Moon- 240,000 it takes 3 days
so in 1 day it travels 240000/3
=80,000
8*10^4 /day
venus- 26,000,000
..
2.6*10^7 is the distance of venus.
it will take
2.6*10^7 / 8*10^4
=325 days ]

Expert answered|shifa saleheen|Points 9374|

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Asked 1/27/2012 5:49:59 PM

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The base of a triangle is 6 cm greater than the height. The area is 20 cm^2. Find the height and the length of the base. **Weegy:** b = h + 8. Area = .5*h*b = .5*h*(h + 8)
.5*h*(h+8) = 24.
h^2 + 8h = 48.
h^2 + 8h - 48 = 0.
(h+12)(h-4) = 0.
h = -12.
h = 4. height of "-12" doesn't make any sense. Trash this solution.
Use h = 4. The base is 8 bigger, that's 12.
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Updated 6/20/2014 10:35:22 AM

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Let h be the height of the triangle, its base is (h + 6).

Area = 1/2*(h + 6)*h = 20

h(h + 6) = 40

h^2 + 6h - 40 = 0

(h + 10)(h - 4) = 0

h = -10 or h = 4.

The height of the triangle is 4cm and the base is 10cm.

Area = 1/2*(h + 6)*h = 20

h(h + 6) = 40

h^2 + 6h - 40 = 0

(h + 10)(h - 4) = 0

h = -10 or h = 4.

The height of the triangle is 4cm and the base is 10cm.

Added 6/20/2014 10:35:22 AM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [6/20/2014 10:41:03 AM]

x^5+4x^4 **Weegy:** 64X^6 (More)

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Updated 6/5/2014 7:49:06 PM

1 Answer/Comment

x^5 + 4x^4 = x^4(x + 4)

Added 6/5/2014 7:49:06 PM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [7/9/2014 10:28:32 AM]

Find the greatest common factor (GCF) of 8x and 12x^3 **Weegy:** The GCF of 8x and 12x^3 is 4x. (More)

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Expert Answered

Updated 7/1/2014 11:57:01 PM

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(6r)^6 (6r)^5 **Weegy:** (6r)^6* (6r)^5 = 46 656r^6*7 776r^5= 362 797 056r^11 (More)

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Expert Answered

Updated 216 days ago|4/30/2023 5:59:13 AM

1 Answer/Comment

When we multiply two exponential expressions with the same base, we can add the exponents:

(6r)^6 × (6r)^5 = 6^6 × r^6 × 6^5 × r^5

6^6 × r^6 × 6^5 × r^5 = 6^(6+5) × r^(6+5) = 6^11 × r^11

Therefore, (6r)^6 × (6r)^5 simplifies to 6^11 × r^11.

(6r)^6 × (6r)^5 = 6^6 × r^6 × 6^5 × r^5

6^6 × r^6 × 6^5 × r^5 = 6^(6+5) × r^(6+5) = 6^11 × r^11

Therefore, (6r)^6 × (6r)^5 simplifies to 6^11 × r^11.

Added 216 days ago|4/30/2023 5:59:13 AM

Find the greatest common factor (GCF) of 6x and 21X^3 **Weegy:** It's 2x.
Find the largest number that divides into both numbers. Multiply that times any variable that's in every term raised to its lowest exponent. (More)

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Expert Answered

Updated 216 days ago|4/30/2023 6:00:14 AM

2 Answers/Comments

The greatest common factor (GCF) of 6x and 21x^3 is 3x.

Added 6/10/2014 10:50:26 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [6/10/2014 10:59:57 PM]

To find the greatest common factor (GCF) of 6x and 21X^3, we need to factor each term into its prime factors and then identify the common factors.

6x can be factored as 2 × 3 × x

21x^3 can be factored as 3 × 7 × x × x × x

The common factors are 3 and x, since both terms have at least one factor of 3 and one factor of x.

Therefore, the greatest common factor of 6x and 21X^3 is 3x.

6x can be factored as 2 × 3 × x

21x^3 can be factored as 3 × 7 × x × x × x

The common factors are 3 and x, since both terms have at least one factor of 3 and one factor of x.

Therefore, the greatest common factor of 6x and 21X^3 is 3x.

Added 216 days ago|4/30/2023 6:00:14 AM

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