Question and answer
Multiply (6z^2 - 4z + 1)(8 - 3z)
Question
Asked 3/9/2016 1:50:33 PM
Updated 3/9/2016 11:05:33 PM
1 Answer/Comment
This answer has been confirmed as correct and helpful.
Edited by Andrew. [3/9/2016 11:05:31 PM], Confirmed by Andrew. [3/9/2016 11:05:33 PM]
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Original conversation
User: Perform the long division (y^3 - 125) ÷ (y - 5)

User: Multiply (6z^2 - 4z + 1)(8 - 3z)

Weegy: (6z^2 - 4z + 1)(8 - 3z) = -18z^3 + 60z^2 - 35z + 8
Johnny_English|Points 97|

User: Simplify b(a + b) - a(a - b).

Weegy: b(a + b) - a(a - b)
= ab + b^2 - (a^2 - ab)
= ab + b^2 - a^2 + ab
= 2ab + b^2 - a^2




Question
Asked 3/9/2016 1:50:33 PM
Updated 3/9/2016 11:05:33 PM
1 Answer/Comment
This answer has been confirmed as correct and helpful.
Edited by Andrew. [3/9/2016 11:05:31 PM], Confirmed by Andrew. [3/9/2016 11:05:33 PM]
New answers
Rating
3
(y^3 - 125)/(y - 5)
= (y - 5)(y^2 + 5y + 25)/(y - 5)
= y^2 + 5y + 25
Added 3/9/2016 5:25:40 PM
This answer has been confirmed as correct and helpful.
Confirmed by Andrew. [3/9/2016 11:05:57 PM]
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Questions asked by the same visitor
Perform the indicated operation. (2u^2 - 7) ÷ (u + 3)
Question
Not Answered
Updated 4/20/2016 6:44:37 PM
1 Answer/Comment
(2u^2 - 7) ÷ (u + 3)
= (2u^2/u+3) - (7/u+3)
= 2u - 6 R. 11
Added 4/20/2016 6:44:35 PM
This answer has been confirmed as correct and helpful.
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