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Find the Circumcenter of triangle ABC with A(1,6), B(1,4), C(5,4).
First, we need to find out the length of each side for this triangle. AB = sqrt [(4 - 6)^2 + (1 - 1)^2] = 2 BC = sqrt [(4 - 4)^2 + (5 - 1)^2] = 4 AC = sqrt [(4 - 6)^2 + (5 - 1)^2] = 2 sqrt5 the Circumcenter of triangle ABC with A(1,6), B(1,4), C(5,4) is 2 + 4 + 2 sqrt 5 = 6 + 2sqrt5.
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Asked 4/4/2014 11:38:08 PM
Updated 4/8/2014 11:25:52 PM
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First, we need to find out the length of each side for this triangle.
AB = sqrt [(4 - 6)^2 + (1 - 1)^2] = 2
BC = sqrt [(4 - 4)^2 + (5 - 1)^2] = 4
AC = sqrt [(4 - 6)^2 + (5 - 1)^2] = 2 sqrt5
the Circumcenter of triangle ABC with A(1,6), B(1,4), C(5,4) is 2 + 4 + 2 sqrt 5 = 6 + 2sqrt5.

Added 4/8/2014 11:25:52 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/8/2014 11:29:59 PM]
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