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Solve 2x = 64
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Asked 6/4/2013 8:57:33 AM
Updated 2/21/2014 2:32:47 PM
2 Answers/Comments
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Flagged by andrewpallarca [2/21/2014 2:31:56 PM]
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User: Solve 2x = 64

Weegy: 2x - 1 = 10 2x = 10 + 1 2x = 11 (divide both sides by 2 to get x) 2x/2 = 11/2 x = 5.5
tk1|Points 41|

User: solve 2x = 1/32

Weegy: 5 (2x - 1) = 6 >> 10x - 5 = 6 >> 10x = 11 >> x = 11/10
SecretAgent|Points 1802|

User: Which of the following points does not lie on the graph of y=32x?

Question
Asked 6/4/2013 8:57:33 AM
Updated 2/21/2014 2:32:47 PM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by andrewpallarca [2/21/2014 2:31:56 PM]
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3
2x = 64

x = 64/2

x = 32
Added 2/21/2014 2:31:54 PM
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3
2x = 1/32

x = (1/32) / 2

x = 1/64
Added 2/21/2014 2:32:47 PM
This answer has been confirmed as correct and helpful.
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Updated 11/16/2016 10:50:01 PM
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An act of fertilization in which genetic information is transferred between cells is called Conjugation.
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Confirmed by Andrew. [11/16/2016 10:50:00 PM]
Which equation could be used to solve y 2+7y=18 by factoring? User: Solve by factoring. x2 - 49 = 0
Weegy: 3-3 = 0 User: If you are solving y 2+2y=48 by completing the square, the next line would be Weegy: the next line is y^2+2y-48=0 User: Solve 2x 2 - 7x - 15 = 0. Weegy: x=0 User: Use the discriminant to describe the roots of each equation. Then select the best description. x2 - 5x - 4 = 0 Weegy: This equation factors to (3x+2)(2x-3) User: Use the discriminant to describe the roots of each equation. Then select the best description. x2 - 5x - 4 = 0 double root real and rational root real and irrational root imaginary root Weegy: B.real and rational root User: Use the discriminant to describe the roots of each equation. Then select the best description. 2x2 + 7x + 6 = 0 double root real and rational root real and irrational root imaginary root Question #3MultipleChoice Score: Use the discriminant to describe the roots of each equation. Then select the best description. 3x2 - 2 + 7x = 0 double rootreal and rational rootreal and irrational rootimaginary root Question #4MultipleChoice Score: Use the discriminant to describe the roots of each equation. Then select the best description. 16x2 + 8x + 1 = 0 double rootreal and rational rootreal and irrational rootimaginary root Question #5MultipleChoice Score: Use the discriminant to describe the roots of each equation. Then select the best description. 7x2 + 3 = 8x double rootreal and rational rootreal and irrational rootimaginary root Question #6MultipleChoice Score: Use the discriminant to describe the roots of each equation. Then select the best description. 3x2 - 10 = 0 double rootreal and rational rootreal and irrational rootimaginary root Question #7MultipleChoice Score: Use the discriminant to describe the roots of each equation. Then select the best description. 6x2 + 13x + 6 = 0 double rootreal and rational rootreal and irrational rootimaginary root Question #8MultipleChoice Score: Use the discriminant to describe the roots of each equation. Then select the best ... (More)
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Not Answered
Updated 5/27/2014 12:00:54 AM
2 Answers/Comments
x^2 - 49 = 0
(x + 7)(x - 7) = 0
x = -7 or x = 7
Added 5/26/2014 11:56:44 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [5/27/2014 12:10:08 AM]
x^2 - 5x - 4 = 0
discriminant = b^2 - 4ac = (-5)^2 - 4(1)(-4) = 41
There are Two Real Irrational Roots for the equation x^2 - 5x - 4 = 0.
Added 5/27/2014 12:00:54 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [5/27/2014 12:10:27 AM]
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