can you solve this math problem for me?

Question

Asked 12/12/2010 6:46:44 PM

Updated 4/16/2014 8:48:49 AM

1 Answer/Comment

This conversation has been flagged as incorrect.

Flagged by yeswey [4/16/2014 8:47:16 AM]

s

Expert answered|rutie|Points 5|

Expert answered|rutie|Points 5|

Expert answered|rutie|Points 5|

Expert answered|rutie|Points 5|

Question

Asked 12/12/2010 6:46:44 PM

Updated 4/16/2014 8:48:49 AM

1 Answer/Comment

This conversation has been flagged as incorrect.

Flagged by yeswey [4/16/2014 8:47:16 AM]

Rating

3

4x(x-7)-5x(x-6)=-3

4x^2 - 28x - 5x^2 + 30x = -3

-x^2 + 2x + 3 = 0

x^2 - 2x - 3 = 0

(x + 1)(x - 3) = 0

x = -1 or x = 3

4x^2 - 28x - 5x^2 + 30x = -3

-x^2 + 2x + 3 = 0

x^2 - 2x - 3 = 0

(x + 1)(x - 3) = 0

x = -1 or x = 3

Added 4/16/2014 8:48:49 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [4/16/2014 8:49:37 AM]

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