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the sum. d^2+d-30/d^2+3d-40 + d^2+14d+48/d^2-2d-48 A. d^2+14d+16 / (d+8)(d-8) B. 2d^2+14d+16/(d+8)(d-8) C. 2d^2+15d+18/(d+8)(d-8)
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Asked 10/1/2012 8:04:19 PM
Updated 4/24/2014 12:41:55 AM
1 Answer/Comment
Flagged by yeswey [4/24/2014 12:41:55 AM]
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User: the sum. d^2+d-30/d^2+3d-40 + d^2+14d+48/d^2-2d-48 A. d^2+14d+16 / (d+8)(d-8) B. 2d^2+14d+16/(d+8)(d-8) C. 2d^2+15d+18/(d+8)(d-8)





Question
Asked 10/1/2012 8:04:19 PM
Updated 4/24/2014 12:41:55 AM
1 Answer/Comment
Flagged by yeswey [4/24/2014 12:41:55 AM]
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(d^2+d-30)/(d^2+3d-40) + (d^2+14d+48)/(d^2-2d-48)
= (d - 5)(d + 6)/(d + 8)(d - 5) + (d + 6)(d + 8)/(d - 8)(d + 6)
= (d + 6)/(d + 8) + (d + 8)/(d - 8)
= (d + 6)(d - 8)/(d + 8)(d - 8) + (d + 8)(d + 8)/(d - 8)(d + 8)
= (d^2 - 2d - 48)/(d + 8)(d - 8) + (d^2 + 16d + 64)/(d + 8)(d - 8)
= (2d^2 + 14d + 16)/(d + 8)(d - 8)
Added 4/24/2014 12:41:51 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/24/2014 12:43:37 AM]
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1 Answer/Comment
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