A person with a mass of 15 kg is walking uphill at a velocity of 2 m/s. What is the walker's momentum?

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A person with a mass of 15 kg is walking uphill at a velocity of 2 m/s so his momentum will be 30 kg m/s. Solution: Momentum (p) = mass (m) * velocity (v) = 15 kg * 2 m/s = 30 kg-m/s

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Asked 79 days ago|3/15/2023 9:51:13 PM

Updated 8 days ago|5/26/2023 6:00:43 AM

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What's the slope of a line that passes through ( 14,13) and (7,0)?

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Updated 81 days ago|3/14/2023 12:24:26 AM

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Rhed°88

Solution:
-13/21 is the slope of a line that passes through (-14,13) and (7,0). Solution: y2-y1/x2-x1; 0-13/ 7-(-14); -13/7+14; -13/21.

Added 81 days ago|3/14/2023 12:24:24 AM

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Solve the equation 3(x – 7) = 42.

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Updated 81 days ago|3/14/2023 12:26:56 AM

1 Answer/Comment

Jozeal

3(x – 7) = 42.
3x - 21 = 42
3x = 42 + 21
3x = 63
x = 21

Added 81 days ago|3/14/2023 12:26:52 AM

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What's the slope of a line that passes through ( 12,15) and (0,4)?

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Updated 81 days ago|3/14/2023 12:31:48 AM

1 Answer/Comment

Rhed°88

The slope of a line that passes through (12,15) and (0,4) is 11/12. m = y2-y1 / x2-x1 ; m = 4 - 15 / 0 -( 12) = 11 / 12 = 11/12.

Added 81 days ago|3/14/2023 12:31:46 AM

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(9.6 × 109) – (8.9 × 109) =

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Updated 81 days ago|3/14/2023 12:37:01 AM

1 Answer/Comment

Aj25

(9.6 × 109) – (8.9 × 109) =76.3

Added 81 days ago|3/14/2023 12:37:01 AM

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Solve the inequality –1 + 6(–1 – 3x) > –39 – 2x.

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Updated 81 days ago|3/14/2023 1:14:33 AM

1 Answer/Comment

Rhed°88

Solution to the inequality:
–1 + 6(–1 – 3x) > –39 – 2x
5-1-3x > -39-2x
-3x + 2x > -39 - 1
-x > -40
x > 40

Added 81 days ago|3/14/2023 1:14:31 AM

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