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If x varies directly as y, and x = 48 when y = 16, find x when y = 5. 5/3, 153.6, 15
x varies directly as y, the equation is x = ky; x = 48 when y = 16, k = x/y = 48/16 = 3 The equation is x = 3y; when y = 5, x = 3(5) = 15
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Asked 3/26/2014 6:21:54 AM
Updated 4/13/2014 11:07:50 PM
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x varies directly as y, the equation is x = ky;
x = 48 when y = 16, k = x/y = 48/16 = 3
The equation is x = 3y;
when y = 5, x = 3(5) = 15
Added 4/13/2014 11:07:50 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/13/2014 11:11:41 PM]
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What is the slope of the line passing through the points (-5, 7) and (-3, 5)? -1/4, -1, 1
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Updated 3/26/2014 7:34:51 AM
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The slope of the line passing through the points (-5, 7) and (-3, 5) is -1.



Added 3/26/2014 7:34:51 AM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [8/7/2014 11:11:39 AM]
Solve x 2 + 2x - 1 = 0
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Updated 4/21/2014 9:22:43 PM
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x^2 + 2x - 1 = 0
a = 1, b = 2, c = -1
b^2 - 4ac = 2^2 - 4(1)(-1) = 8
x = [-2 ± sqrt(8)]/2
= -1 ± sqrt(2)
The solution for the equation x^2 + 2x - 1 = 0 is x = -1 + sqrt(2) or x = -1 - sqrt(2)
Added 4/21/2014 9:19:47 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/21/2014 9:21:29 PM]
9x^2 + 4y^2 - 36 = 0
9x^2 + 4y^2 = 36
x^2/4 + y^2/9 = 1
The type of conic section for the equation 9x^2 + 4y^2 - 36 = 0 is ellipse.
Added 4/21/2014 9:22:43 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/21/2014 9:37:47 PM]
Select the conic section that represents the equation. 20x = 4y 2 parabola, circle, hyperbola, ellipse
Question
Updated 4/21/2014 8:43:04 PM
1 Answer/Comment
The conic section that represents the equation 20x = 4y^2 is: Parabola.
Added 4/21/2014 8:43:04 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/21/2014 8:50:56 PM]
What type of conic section is the following equation? 5x2 - y = 12
Question
Updated 3/25/2014 7:47:43 PM
1 Answer/Comment
The type of conic section for the equation 5x^2 - y = 12 is Parabolas.
The "vertex" form of a parabola with its vertex at (h, k) is:
y = a(x – h)^2 + k
Added 3/25/2014 7:47:43 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [3/25/2014 7:51:08 PM], Unconfirmed by jeifunk [3/25/2014 7:51:08 PM], Confirmed by jeifunk [3/25/2014 7:51:10 PM], Unconfirmed by jeifunk [3/25/2014 7:51:10 PM], Confirmed by jeifunk [3/25/2014 7:51:11 PM], Unconfirmed by jeifunk [3/25/2014 7:51:11 PM], Confirmed by jeifunk [3/25/2014 7:51:12 PM]
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