What is the equation of a circle that has a center at point T (-3,-1) and passes through the point (1,-6)

First we need to find out the radius of the circle, radius = sqrt[(-5)^2+4^2] = sqrt(41) The equation of a circle that has a center at point T (-3,-1) and passes through the point (1,-6) is (x + 3)^2 + (y + 1)^2 = 41

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Asked 4/3/2014 7:40:21 AM

Updated 4/21/2014 8:27:26 PM

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First we need to find out the radius of the circle, radius = sqrt[(-5)^2+4^2] = sqrt(41)

The equation of a circle that has a center at point T (-3,-1) and passes through the point (1,-6) is (x + 3)^2 + (y + 1)^2 = 41

The equation of a circle that has a center at point T (-3,-1) and passes through the point (1,-6) is (x + 3)^2 + (y + 1)^2 = 41

Added 4/21/2014 8:27:26 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [4/21/2014 8:32:46 PM]

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