Question and answer
Multiply: 4x^3*2x^12
Question
Asked 3/25/2013 4:55:08 PM
Updated 7/31/2014 4:06:28 PM
2 Answers/Comments
This answer has been confirmed as correct and helpful.
Edited by andrewpallarca [7/31/2014 4:05:02 PM], Confirmed by andrewpallarca [7/31/2014 4:05:04 PM]
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Original conversation
User: Multiply: 4x^3*2x^12

Weegy: 4x^3*2x^12 = 8x^15.
ArslanBasit|Points 1945|

User: . Divide: 6x^3/2x

User: find: (x^5)^3

Weegy: (x^5)^3 = x^15
Expert answered|emdjay23|Points 673|

Question
Asked 3/25/2013 4:55:08 PM
Updated 7/31/2014 4:06:28 PM
2 Answers/Comments
This answer has been confirmed as correct and helpful.
Edited by andrewpallarca [7/31/2014 4:05:02 PM], Confirmed by andrewpallarca [7/31/2014 4:05:04 PM]
New answers
Rating
8
6x^3/2x = 3x^2
Added 7/31/2014 4:06:28 PM
This answer has been confirmed as correct and helpful.
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Questions asked by the same visitor
Multiply and Simplify: (x - 4)(x + 3)
Question
Updated 6/27/2014 10:37:51 AM
1 Answer/Comment
(x - 4)(x + 3)
=x^2+3x-4x-12
=x^2-x-12
Added 6/27/2014 10:37:50 AM
This answer has been confirmed as correct and helpful.
Multiply and Simplify: (x - 4)(x + 3)
Question
Not Answered
Updated 3/26/2013 3:27:20 AM
1 Answer/Comment
(x - 4)(x + 3)

x^2- 4x + 3x - 12

= x^2 - x - 12
Added 3/26/2013 3:27:20 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [6/17/2014 2:22:37 PM]
Multiply and Simplify: (x - 4)(x + 3)
Weegy: 3-3 = 0 User: Factor out the largest possible common factor (the GCF) from: 2xy^2 +8xy^2 Weegy: 2xy is the GCF of that problem. (More)
Question
Updated 8/19/2014 12:29:39 AM
3 Answers/Comments
(x - 4)(x + 3)

x^2 - 4x + 3x - 12

= x^2 - x - 12
Added 3/26/2013 3:26:27 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [6/17/2014 2:22:42 PM]
The GCF of 2xy^2 +8xy^2 is 10xy2.
Added 8/18/2014 8:02:07 AM
This answer has been flagged as incorrect.
Flagged by yeswey [8/19/2014 12:29:23 AM]
The GCF of 2xy^2 + 8xy^2 is 2xy^2.
Added 8/19/2014 12:29:39 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [8/19/2014 12:44:06 AM]
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