Choose the equation that could be used to find three consecutive integers whose sum is 75.
n + (n + 1) + (n + 2) = 75
n + (n + 2) + (n + 4) = 75
n + (n + 1) + (n + 3) = 75
n + (n - 1) + (n - 3) = 75

n + (n + 1) + (n + 2) = 75 is the equation that could be used to find three consecutive integers whose sum is 75. Solution: n + (n + 1) + (n + 2) = 75; 3n + 3 = 75; 3n = 75 - 3; 3n = 72; n = 72/3; n = 24, the next two integers are 25 and 26. 24 + 25 + 26 = 75

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Asked 4/12/2013 2:07:17 PM

Updated 11/16/2014 4:46:29 PM

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n + (n + 1) + (n + 2) = 75 is the equation that could be used to find three consecutive integers whose sum is 75.

Solution:

n + (n + 1) + (n + 2) = 75;

3n + 3 = 75;

3n = 75 - 3;

3n = 72;

n = 72/3;

n = 24, the next two integers are 25 and 26.

24 + 25 + 26 = 75

Solution:

n + (n + 1) + (n + 2) = 75;

3n + 3 = 75;

3n = 75 - 3;

3n = 72;

n = 72/3;

n = 24, the next two integers are 25 and 26.

24 + 25 + 26 = 75

Added 11/16/2014 4:46:29 PM

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