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Write the equation of the given circle. center (1, -5) radius of 10
The equation of the circle with center (1, -5) radius of 10 is (x - 1)^2 + (y + 5)^2 = 100.
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Asked 6/10/2013 9:48:35 AM
Updated 7/3/2014 8:34:36 PM
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The equation of the circle with center (1, -5) radius of 10 is (x - 1)^2 + (y + 5)^2 = 100.
Added 7/3/2014 8:34:36 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 10:18:40 PM]
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Questions asked by the same visitor
Find the product of (5a - 7)(2a - 1)?
Question
Updated 1/28/2018 7:24:33 AM
1 Answer/Comment
(5a - 7)(2a - 1)
= 10a^2 - 5a - 14a + 7
= 10^2 - 19a + 7
Added 1/28/2018 7:24:33 AM
This answer has been confirmed as correct and helpful.
Write the equation of the given circle. center (-2, -2) radius of 6
Weegy: (x + 2)2 + (y - 4)2 = 49 User: The foci are located at (6, 0) and (-6, 0) (0, 6) and (0, -6) (0, 8) and (0, -8) (More)
Question
Updated 7/3/2014 8:41:11 PM
1 Answer/Comment
The equaton of the circle with center (-2, -2) radius of 6 is (x + 2)^2 + (y + 2)^2 = 36.
Added 7/3/2014 8:40:56 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:02:02 PM]
Write the equation of the given circle. center (3, 3) radius of 2
Question
Not Answered
Updated 7/3/2014 8:40:00 PM
2 Answers/Comments
The equation of the circle with center (3, 3) and radius 2 is (x - 3)^2 + (y - 3)^2 = 4.
Added 7/3/2014 8:40:00 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:02:41 PM]
The equation of the circle whose center is at (2, 1) and radius is 3 is
Weegy: First know the equation of a circle. (x-h)^2 + (y-k)^2 = r^2. Now it becomes easy. You plug in 5 for x and 6 for y. You plug in 3 for r. That will be your equation. (5-h)^2 + (6-k)^2 = 9. (More)
Question
Updated 7/3/2014 8:38:35 PM
1 Answer/Comment
The equation of the circle whose center is at (2, 1) and radius is 3 is (x - 2)^2 + (y - 1)^2 = 9.
Added 7/3/2014 8:38:35 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:02:51 PM]
Find the distance between the points (-3, 2) and (4, -5). v10 7v2 2v2
Weegy: x^-3/y^-5 = y^5/x^3 User: The radius of the circle whose equation is (x + 4)² + (y - 2)² = 36 is 36 18 6 Question #19MultipleChoice Score: Find the length of the line segment that joins the points (2, 5) and (9, 8). v10v52v58 Question #20DragAndDrop Score: Click an item in the list or group of pictures at the bottom of the problem and holding your mouse button down, drag it into the correct position in the area. Release your mouse button when the item is place. If you change your mind, double-click one item to remove it, or click the Start Over button to clear all of your answers.Write the equation of the given circle. center (3, 3) radius of 2 Question #21MultipleChoice Score: The center of the circle whose equation is (x + 1)² + (y + 2)² = 49 is (1, 2)(-1, -2)(1, -2) Question #22DragAndDrop Score: Click an item in the list or group of pictures at the bottom of the problem and holding your mouse button down, drag it into the correct position in the area. Release your mouse button when the item is place. If you change your mind, double-click one item to remove it, or click the Start Over button to clear all of your answers.Write the equation of the given circle. center (-2, -2) radius of 6 Question #23MultipleChoice Score: Skipped The minor intercepts are at (±2, 0)(0, ±2)(±5, 0) Question #24MultipleChoice Score: The radius of the circle whose equation is (x - 3)² + (y + 1)² = 16 is 4816 Question #25MultipleChoice Score: The center of the circle whose equation is (x - 2)2 + (y + 4)2 = 25 is (2, 4)(-2, 4)(2, -4) (More)
Question
Updated 7/3/2014 8:31:06 PM
1 Answer/Comment
The distance between the points (-3, 2) and (4, -5) is sqrt =(4+3)^2+(-5-2)^2] = sqrt (49+49) = sqrt 98 = 7v2
Added 7/3/2014 8:31:06 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 10:19:07 PM]
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