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What is the solution set of the following equation? (2x - 5)(3x + 1) = 0
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Asked 6/7/2013 7:05:02 AM
Updated 7/4/2014 1:56:57 AM
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Flagged by yeswey [7/4/2014 1:54:39 AM]
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User: What is the solution set of the following equation? (2x - 5)(3x + 1) = 0

Weegy: x = 27/4
javedsarkar|Points 1015|

User: Choose the equation that models the following problem. When the side of a square is doubled, its area is increased to 28 cm2. 2x= 28 2x2= 28 (2x)2= 28 2x=x2+ 28

Weegy: The sides of the square are both 8cm(its a square, and 8 squared is 64) So the diameter of the circle is 8cm, and the radius is 4. The area = pi(4^2) = 16pi.
ruinmayer|Points 0|

User: Determine the solution set of (x + 2)2 = 36.

Question
Asked 6/7/2013 7:05:02 AM
Updated 7/4/2014 1:56:57 AM
3 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [7/4/2014 1:54:39 AM]
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(2x - 5)(3x + 1) = 0
2x - 5 = 0 or 3x + 1 = 0
x = 5/2 or x = -1/3
The solution set for the equation (2x - 5)(3x + 1) = 0 is {5/2, -1/3)
Added 7/4/2014 1:54:33 AM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 3:02:02 PM]
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When the side of a square is doubled, its area is increased to 28 cm^2. The equation for the problem is (2x)^2= 28 where x is the side of the square.
Added 7/4/2014 1:55:52 AM
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Confirmed by yumdrea [7/4/2014 3:02:04 PM]
3
(x + 2)^2 = 36
x + 2 = 6 or x + 2 = -6
x = 4 or x = -8
The solution set for the equation (x + 2)^2 = 36 is {4, -8}
Added 7/4/2014 1:56:57 AM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 3:02:03 PM]
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