Find the zeros of the polynomial function. f(x) = x3 + x2 - 42x
f(x) = x^3 + x^2 - 42x; x(x + 7)(x - 6) = 0; x = 0; x + 7 = 0; x = -7; x - 6 = 0; x = 6 The zeros of the polynomial function f(x) = x^3 + x^2 - 42x are 0, -7, 6
Question
Updated 8/28/2014 1:50:36 AM
Rating
3
f(x) = x^3 + x^2 - 42x;
x(x + 7)(x - 6) = 0;
x = 0;
x + 7 = 0; x = -7;
x - 6 = 0; x = 6
The zeros of the polynomial function f(x) = x^3 + x^2 - 42x are
0, -7, 6

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Updated 8/28/2014 1:47:56 AM
f(x) = x^3 + 4x^2 - 9x - 36; f(x) = 0
(x + 4)(x - 3)(x + 3);
x + 4 = 0; x = -4;
x - 3 = 0; x = 3;
x + 3 = 0; x = -3
The zeroes of the polynomial function f(x) = x^3 + 4x^2 - 9x - 36 are:
-4, 3, -3
Multiply. -8x2(-10x4 + 9x3)
Question
Updated 8/12/2014 1:44:20 AM
-8x^2(-10x^4 + 9x^3) = 80x^6 - 72x^5
Confirmed by jeifunk [8/12/2014 1:57:18 AM]
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