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x 2 - y 2 = 16 line circle ellipse parabola hyperbola
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Asked 6/10/2013 10:25:43 AM
Updated 7/3/2014 8:25:08 PM
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User: x 2 - 4x + y 2 - 4y + 4 = 12 line circle ellipse parabola hyperbola

User: x 2 - y 2 = 16 line circle ellipse parabola hyperbola

Weegy: The slope of this equation is 4.
vchutkan|Points 5755|

User: xy = 25 line circle ellipse parabola hyperbola

User: 16y = x 2 line circle ellipse parabola hyperbola

Weegy: The answer is "parabola "
bonaxle|Points 789|

Question
Asked 6/10/2013 10:25:43 AM
Updated 7/3/2014 8:25:08 PM
2 Answers/Comments
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The conic section for the equation x^2 - 4x + y^2 - 4y + 4 = 12 is a circle.
x^2 - 4x + y^2 - 4y + 4 = 12
(x^2 - 4x + 4) + (y^2 - 4y + 4) = 12 + 4
(x - 2)^2 + (y - 2)^2 = 16
it is a circle with center (2, 2) and radius = 4.
Added 7/3/2014 8:22:33 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 1:58:09 PM]
3
The conic setion for the equation x^2 - y^2 = 16 is a hyperbola.
Added 7/3/2014 8:25:08 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 1:58:09 PM]
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Find the product of (5a - 7)(2a - 1)?
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Updated 295 days ago|1/28/2018 7:24:33 AM
1 Answer/Comment
(5a - 7)(2a - 1)
= 10a^2 - 5a - 14a + 7
= 10^2 - 19a + 7
Added 295 days ago|1/28/2018 7:24:33 AM
This answer has been confirmed as correct and helpful.
Write the equation of the given circle. center (-2, -2) radius of 6
Weegy: (x + 2)2 + (y - 4)2 = 49 User: The foci are located at (6, 0) and (-6, 0) (0, 6) and (0, -6) (0, 8) and (0, -8) (More)
Question
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Updated 7/3/2014 8:41:11 PM
1 Answer/Comment
The equaton of the circle with center (-2, -2) radius of 6 is (x + 2)^2 + (y + 2)^2 = 36.
Added 7/3/2014 8:40:56 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:02:02 PM]
The equation of the circle whose center is at (2, 1) and radius is 3 is
Weegy: First know the equation of a circle. (x-h)^2 + (y-k)^2 = r^2. Now it becomes easy. You plug in 5 for x and 6 for y. You plug in 3 for r. That will be your equation. (5-h)^2 + (6-k)^2 = 9. (More)
Question
Expert Answered
Updated 7/3/2014 8:38:35 PM
1 Answer/Comment
The equation of the circle whose center is at (2, 1) and radius is 3 is (x - 2)^2 + (y - 1)^2 = 9.
Added 7/3/2014 8:38:35 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:02:51 PM]
Write the equation of the given circle. center (3, 3) radius of 2
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Not Answered
Updated 7/3/2014 8:40:00 PM
2 Answers/Comments
The equation of the circle with center (3, 3) and radius 2 is (x - 3)^2 + (y - 3)^2 = 4.
Added 7/3/2014 8:40:00 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:02:41 PM]
Write the equation of the given circle. center (1, -5) radius of 10
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Updated 7/3/2014 8:34:36 PM
1 Answer/Comment
The equation of the circle with center (1, -5) radius of 10 is (x - 1)^2 + (y + 5)^2 = 100.
Added 7/3/2014 8:34:36 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 10:18:40 PM]
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