factor the trinomial. a^3 - 2a^2 -15a

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Asked 3/20/2012 1:53:57 PM

Updated 9/27/2014 6:06:06 AM

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Flagged by janezeshun [9/27/2014 6:05:12 AM]

s

Expert answered|johnlennons|Points 447|

Question

Asked 3/20/2012 1:53:57 PM

Updated 9/27/2014 6:06:06 AM

1 Answer/Comment

This conversation has been flagged as incorrect.

Flagged by janezeshun [9/27/2014 6:05:12 AM]

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a^3 - 2a^2 -15a

=a ( a^2 -2a - 15)

= a ( a^2 - 5a + 3a -15)

=a (a - 5) ( a + 3)

=a ( a^2 -2a - 15)

= a ( a^2 - 5a + 3a -15)

=a (a - 5) ( a + 3)

Added 9/27/2014 6:06:06 AM

This answer has been confirmed as correct and helpful.

solve for v.... 6/v=9/v-1/2

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Expert Answered

Updated 9/20/2014 10:57:20 PM

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6/v=9/v-1/2

6/v - 9/v = -1/2

-3/v = -1/2

v = -3/( -1/2)

v= -3 *(-2)

v = 6

6/v - 9/v = -1/2

-3/v = -1/2

v = -3/( -1/2)

v= -3 *(-2)

v = 6

Added 9/20/2014 10:56:18 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [9/20/2014 11:00:45 PM]

multiply... (4x+4)(6x^2 +8x+3) **Weegy:** a.
Factor as:
(x - 3)(x + 1)^3 = 0
zeros are at x = 3 and x = -1
y ' = 4x^3 - 12x - 8
4(x - 2)(x + 1)^2
zeros at x = 2 and x = -1
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b.
y " = 12x^2 - 12
y "(2) = 36 which is positive, [ so x = 2 is a minimum point
y "(-1) = 0, an inflection point
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c.
f(x) decreases from [-8, 2] and increases from [2, +8]
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d.
f(x) is negative for x = [-1, 3] and positive for all other real values ] (More)

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Expert Answered

Updated 3/21/2012 11:26:01 AM

3 Answers/Comments

(4x+4)(6x^2 +8x+3) = 24x^3 + 56x^2 + 44x + 12

Added 3/20/2012 10:42:09 AM

This answer has been confirmed as correct and helpful.

Unflagged by andrewpallarca [7/7/2014 7:25:01 PM], Confirmed by andrewpallarca [7/7/2014 7:25:03 PM]

multiply (s+f)(s^2 - sf +f^2)
**Weegy:** f^3 + s^3 is the answer. (s+f)(s^2 - sf +f^2) = f^3 + s^3 (More)

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Asked 3/20/2012 12:48:15 PM

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multiply (r+1/5)(r+1/4)
**Weegy:** r^2 + 9r/20 + 1/20 (More)

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Asked 3/20/2012 1:17:17 PM

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factor completely... 4x^8 - 12x^7 + 24x^6
**Weegy:** 4x^8 - 12x^7 + 24x^6
= 4x^6 (x^2 - 3x + 6) (More)

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Updated 7/11/2014 12:10:08 AM

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