Factor out the greatest common factor.
16y^5 24y^4 40y^3

Question

Asked 6/8/2013 8:22:36 PM

Updated 6/22/2014 3:29:26 AM

2 Answers/Comments

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Question

Asked 6/8/2013 8:22:36 PM

Updated 6/22/2014 3:29:26 AM

2 Answers/Comments

Rating

8

(6x^2-31x+5)/(x-5)

= (x - 5)(6x - 1)/(x - 5)

= 6x - 1

= (x - 5)(6x - 1)/(x - 5)

= 6x - 1

Added 6/22/2014 3:15:49 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [6/22/2014 10:29:10 AM]

8

(5.9x^3+3.4x^2-7)-(29x^3-9.6x^2+3)

= 5.9x^3+3.4x^2-7-29x^3+9.6x^2-3

= (5.9x^3-29x^3)+(3.4x^2+9.6x^2)-(7+3)

= -23.1x^3+13x^2-10

= 5.9x^3+3.4x^2-7-29x^3+9.6x^2-3

= (5.9x^3-29x^3)+(3.4x^2+9.6x^2)-(7+3)

= -23.1x^3+13x^2-10

Added 6/22/2014 3:29:26 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [6/22/2014 10:30:13 AM]

16y^2 - 8y + 1

Question

Not Answered

Updated 3/12/2017 1:44:27 AM

1 Answer/Comment

16y^2 - 8y + 1 = (4y - 1)^2

Added 3/12/2017 1:44:27 AM

This answer has been confirmed as correct and helpful.

Factor out the greatest common factor.
16y^5 24y^4 40y^3
**Weegy:** The largest common factor is 8y^3 **User:** 2bc+8b-3c-12 what is the answer **Weegy:** 2bc+8b-3c-12, the alternate/factored form is (2b-3)(c+4). Do you have a specific question about 2bc+8b-3c-12. **User:** (16x^2-56x+40)/8 **Weegy:** 2x^(2)-7x+5 is the answer..
....(16x^(2)-56x+40)/(8)...
Factor out the GCF of 8 from each term in the polynomial.
(8(2x^(2))+8(-7x)+8(5))/(8)...
Factor out the GCF of 8 from 16x^(2)-56x+40.
(8(2x^(2)-7x+5))/(8)...
Find the factors such [ that the product of the factors is the trinomial 2x^(2)-7x+5. This can be done by trial and error and checked using the FOIL method of simplifying polynomials.
(8(x-1)(2x-5))/(8)...
Reduce the expression (8(x-1)(2x-5))/(8) by removing a factor of 8 from the numerator and denominator.
(x-1)(2x-5)...
Multiply each term in the first group by each term in the second group using the FOIL method. FOIL stands for First Outer Inner Last, and is a method of multiplying two binomials. First, multiply the first two terms in each binomial group. Next, multiply the outer terms in each group, followed by the inner terms. Finally, multiply the last two terms in each group.
(x*2x+x*-5-1*2x-1*-5)...
Simplify the FOIL expression by multiplying and combining all like terms.
(2x^(2)-7x+5)...
Remove the parentheses around the expression 2x^(2)-7x+5.
2x^(2)-7x+5... ] **User:** 12w^4-6w^3+w^2 **Weegy:** Hello
your ans is
Mathematically speaking, integral (w^2-6 w^3+12 w^4) dw = (12 w^5)/5-(3 w^4)/2+w^3/3+constant w = 0 w = 1/12 (3-i sqrt(3)). (More)

Question

Expert Answered

Updated 5/26/2014 11:39:54 PM

2 Answers/Comments

(16x^2-56x+40)/8 = 2x^2 - 7x + 5

Added 5/26/2014 11:39:05 PM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [5/26/2014 11:42:58 PM]

12w^4-6w^3+w^2 = w^2(12w^2 - 6w + 1)

Added 5/26/2014 11:39:54 PM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [5/26/2014 11:43:17 PM]

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