Factor out the greatest common factor. 16y^5 24y^4 40y^3
Question
Updated 6/22/2014 3:29:26 AM
s
Original conversation
User: Factor out the greatest common factor. 16y^5 24y^4 40y^3

Weegy: The largest common factor is 8y^3
rhey22787|Points 1476|

User: (x^3+2x^2-3x+2)/(x+1)

Weegy: (x^3+2x^2-3x+2)?(x+1) = x^2+x-4 with a remainder of 6.
andrewpallarca|Points 22394|

User: (6x^2-31x+5)/(x-5)

User: (5.9x^3+3.4x^2-7)-(29x^3-9.6x^2+3)

Weegy: The answer is =45x^3+12x^2 -7 -18x^3 +54x^2 -3 take the like terms together and simplify 45x^3-18x^3 +12x^2+54x^2 -7-3 => (45-18)x^3 + (12+54)x^2 -(7+3) => 27x^3 + 66x^2 -10
uxiali|Points 1577|

User: x^2+12x+11

Weegy: It will be c.x < 2. Please, rate the answer ?Good? and let us grow if you are satisfied. Thank you for the interest. Best wishes.
shifa saleheen|Points 9966|

User: x2+12x+11

Weegy: If you factor that out, it would be (x+11) and (x+1).. If you multiply 11 and 1 you'll have +11, which is the last term and if you add 11 and 1, you'll have 12, which is the middle term.

Question
Updated 6/22/2014 3:29:26 AM
Rating
8
(6x^2-31x+5)/(x-5)
= (x - 5)(6x - 1)/(x - 5)
= 6x - 1
Confirmed by andrewpallarca [6/22/2014 10:29:10 AM]
8
(5.9x^3+3.4x^2-7)-(29x^3-9.6x^2+3)
= 5.9x^3+3.4x^2-7-29x^3+9.6x^2-3
= (5.9x^3-29x^3)+(3.4x^2+9.6x^2)-(7+3)
= -23.1x^3+13x^2-10
Confirmed by andrewpallarca [6/22/2014 10:30:13 AM]

Questions asked by the same visitor
12x^2-5x-3
Question
Updated 6/22/2014 4:40:01 AM
12x^2 - 5x - 3 = (3x + 1)(4x - 3)
Confirmed by yumdrea [6/22/2014 3:54:13 PM]
16y^2 - 8y + 1
Question
Updated 3/12/2017 1:44:27 AM
16y^2 - 8y + 1 = (4y - 1)^2
Factor out the greatest common factor. 16y^5 24y^4 40y^3
Weegy: The largest common factor is 8y^3 User: 2bc+8b-3c-12 what is the answer Weegy: 2bc+8b-3c-12, the alternate/factored form is (2b-3)(c+4). Do you have a specific question about 2bc+8b-3c-12. User: (16x^2-56x+40)/8 Weegy: 2x^(2)-7x+5 is the answer.. ....(16x^(2)-56x+40)/(8)... Factor out the GCF of 8 from each term in the polynomial. (8(2x^(2))+8(-7x)+8(5))/(8)... Factor out the GCF of 8 from 16x^(2)-56x+40. (8(2x^(2)-7x+5))/(8)... Find the factors such [ that the product of the factors is the trinomial 2x^(2)-7x+5. This can be done by trial and error and checked using the FOIL method of simplifying polynomials. (8(x-1)(2x-5))/(8)... Reduce the expression (8(x-1)(2x-5))/(8) by removing a factor of 8 from the numerator and denominator. (x-1)(2x-5)... Multiply each term in the first group by each term in the second group using the FOIL method. FOIL stands for First Outer Inner Last, and is a method of multiplying two binomials. First, multiply the first two terms in each binomial group. Next, multiply the outer terms in each group, followed by the inner terms. Finally, multiply the last two terms in each group. (x*2x+x*-5-1*2x-1*-5)... Simplify the FOIL expression by multiplying and combining all like terms. (2x^(2)-7x+5)... Remove the parentheses around the expression 2x^(2)-7x+5. 2x^(2)-7x+5... ] User: 12w^4-6w^3+w^2 Weegy: Hello your ans is Mathematically speaking, integral (w^2-6 w^3+12 w^4) dw = (12 w^5)/5-(3 w^4)/2+w^3/3+constant w = 0 w = 1/12 (3-i sqrt(3)). (More)
Question
Updated 5/26/2014 11:39:54 PM
(16x^2-56x+40)/8 = 2x^2 - 7x + 5
Confirmed by andrewpallarca [5/26/2014 11:42:58 PM]
12w^4-6w^3+w^2 = w^2(12w^2 - 6w + 1)
Confirmed by andrewpallarca [5/26/2014 11:43:17 PM]
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