Multiply and simplify:
(3x2 – 2x – 1)(x2 + x + 5)
A. 3x4 + 2x3 + 12x2 – 11x – 5
B. 3x4 + x3 + 12x2 – 10x – 5
C. 3x4 + x3 + 12x2 – 11x – 5
D. 3x4 + x3 + 14x2 – 11x – 5

(3x^2 – 2x – 1)(x^2 + x + 5) = 3x^4 - 2x^3 + 3x^3 - x^2 - 2x^2 + 15x^2 - x - 10x - 5 = 3x^4 + x^3 + 12x^2 - 11x - 5

s

Question

Asked 4/30/2012 11:58:09 AM

Updated 7/13/2014 1:57:28 PM

1 Answer/Comment

Rating

3

(3x^2 – 2x – 1)(x^2 + x + 5)

= 3x^4 - 2x^3 + 3x^3 - x^2 - 2x^2 + 15x^2 - x - 10x - 5

= 3x^4 + x^3 + 12x^2 - 11x - 5

= 3x^4 - 2x^3 + 3x^3 - x^2 - 2x^2 + 15x^2 - x - 10x - 5

= 3x^4 + x^3 + 12x^2 - 11x - 5

Added 7/13/2014 1:57:28 PM

This answer has been confirmed as correct and helpful.

9x + 8 = 2x + 8
**Weegy:** 9x + 8 = 2x + 8,
9x - 2x = 8 - 8
7x = 0
x = 0/7
x = 0
(More)

Question

Expert Answered

Updated 6/16/2014 2:11:11 PM

0 Answers/Comments

Multiply and simplify.
(3x – 1)(2x + 5)
A. 6x2 – 13x – 5
B. 6x2 – 17x – 5
C. 6x2 + 13x – 5
D. 6x2 + 17x – 5

Question

Not Answered

Updated 6/16/2014 2:10:48 PM

1 Answer/Comment

(3x – 1)(2x + 5)

= 6x^2 + 15x - 2x - 5

= 6x^2 + 13x - 5

= 6x^2 + 15x - 2x - 5

= 6x^2 + 13x - 5

Added 6/16/2014 2:10:48 PM

This answer has been confirmed as correct and helpful.

2*2 **Weegy:** 2^2 means 2*2 or square of 2 whiach is equal to 4. So Ans. =4 **User:** Is the algebraic expression a polynomial? If so, give its degree.
9x3 + 6x6 + 8
**User:** Perform the indicated operations and simplify.
5x – 4x[8 – 3(x – 2)]
**Weegy:** 12x^2-51x (More)

Question

Expert Answered

Updated 7/16/2014 1:51:00 AM

2 Answers/Comments

5x – 4x[8 – 3(x – 2)]

= 5x - 4x(8 - 3x + 6)

= 5x - 4x(14 - 3x)

= 5x - 56x + 12x^2

= 12x^2 - 51x

= 5x - 4x(8 - 3x + 6)

= 5x - 4x(14 - 3x)

= 5x - 56x + 12x^2

= 12x^2 - 51x

Added 7/16/2014 1:49:53 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [7/16/2014 4:13:52 AM]

The algebraic expression 9x^3 + 6x^6 + 8 is a polynomial, it's degree is 6.

Added 7/16/2014 1:51:00 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [7/16/2014 4:14:18 AM]

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