Find the maximum or minimum of the following quadratic function: y =x2

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Find the maximum or minimum of the following quadratic function: y =x2 - 10x + 25.

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Asked 9/6/2012 10:30:13 PM

Updated 108 days ago|8/29/2025 9:29:48 AM

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User: Find the maximum or minimum of the following quadratic function: y =x2 - 10x + 25.

Weegy: Example Find the x- and y- intercepts of the quadratic function f(x) = 1.5x2 - 3.2x - 9.6. Solution The y-intercept is found by replacing x with 0: f(0) = 1.5(0)2 - 3.2(0) - 9.6 = -9.6. [ Thus the y-intercept is the point (0, -9.6). The x-intercepts are found by replacing y or f(x) with 0 and solving for x: 0 = 1.5x2 - 3.2x - 9.6. Using the quadratic formula, we get ]
Expert answered|dandix14|Points 195|

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Asked 9/6/2012 10:30:13 PM

Updated 108 days ago|8/29/2025 9:29:48 AM

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cruz30

Identify the form
The function is in the form y = ax^2 + bx + c, where a = 1, b = -10, c = 25.
Since a > 0, the parabola opens upward, so it has a minimum.
Find the x-coordinate of the vertex
x = -b / (2a) = -(-10) / (2 * 1) = 10 / 2 = 5
Find the y-coordinate of the vertex
y = (5)^2 - 10(5) + 25 = 25 - 50 + 25 = 0
Answer: The minimum value is 0 at x = 5

Added 108 days ago|8/29/2025 9:29:48 AM

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What is the solution of -5x > 25? A. x > -5 B. x 5 D. x < 5

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Updated 2/7/2017 9:06:20 PM

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Andrew.

-5x > 25
x < 25/-5
x < -5

Added 2/7/2017 9:06:20 PM

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when you have a problem like this: -5x > 25 i did the work and got down to this: -1x>-5 What do you do next?

Weegy: divide -1 on both sides this will give you x>5 ,but since we divided by negative. The inequality sign flips also so x<5 is your answer. (More)

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