Question and answer
Locate the gerund (not the gerund phrase) and identify its use. I always enjoy eating a midnight snack. Gerund: Noun Use:
I always enjoy eating a midnight snack. Gerund: eating Noun Use: direct object
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patmarone|Points 6147|
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Asked 9/18/2012 9:30:19 AM
Updated 11/15/2015 8:51:27 AM
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This answer has been confirmed as correct and helpful.
Edited by Andrew. [11/15/2015 8:51:23 AM], Confirmed by Andrew. [11/15/2015 8:51:27 AM]
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Questions asked by the same visitor
What type of conic section is the following equation? 5x2 - y = 12 parabola circle hyperbola ellipse
Question
Updated 7/11/2014 9:04:52 AM
1 Answer/Comment
The conic section for the equation 5x^2 - y = 12 is parabola.
Added 7/11/2014 9:04:52 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [7/11/2014 9:11:55 AM]
What type of conic section is the following equation? 16x2 - 300 - 25y2 = 100 parabola circle hyperbola ellipse
Weegy: The answer is Circle. (More)
Question
Expert Answered
Updated 7/11/2014 8:58:01 AM
1 Answer/Comment
The section for the equation 16x^2 - 300 - 25y^2 = 100 is hyperbola.
16x^2 - 300 - 25y^2 = 100
16x^2 - 25y^2 = 100 + 300
16x^2 - 25y^2 = 400
x^2/25 - y^2/16 = 1
Added 7/11/2014 8:57:48 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [7/11/2014 8:59:59 AM]
Roman numerals in an outline signify main ideas. True False
Weegy: Roman numerals in an outline signify main ideas. TRUE. (More)
Question
Updated 5/31/2016 12:24:18 AM
0 Answers/Comments
What type of conic section is the following equation? 9x2 + 4y2 - 36 = 0 parabola circle hyperbola ellipse
Question
Updated 7/11/2014 8:53:54 AM
1 Answer/Comment
The conic section for the equation 9x^2 + 4y^2 - 36 = 0 is ellipse.
9x^2 + 4y^2 - 36 = 0
9x^2 + 4y^2 = 36
x^2/4 + y^2/9 = 1
Added 7/11/2014 8:53:54 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [7/11/2014 9:00:35 AM]
What type of conic section is the following equation? 4x2 + 4(y2 - 4) = 0 parabola circle hyperbola ellipse
Question
Updated 7/11/2014 9:00:16 AM
1 Answer/Comment
The conic section for the equation 4x^2 + 4(y^2 - 4) = 0 is circle.
4x^2 + 4(y^2 - 4) = 0
4x^2 + 4y^2 - 16 = 0
4x^2 + 4y^2 = 16
x^2 + y^2 = 4 which is the equation for a circle with center (0, 0) and radius 2.
Added 7/11/2014 9:00:16 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [7/11/2014 9:02:18 AM]
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