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Find the possible value or values of y in the quadratic equation 4 – 4y – y2 = 0. A. y = 2 B. y = –3, y = –1 C. y = –2 + 2 2, y = 2 2 2 D. y = –4, y = 1
The possible value or values of y in the quadratic equation 4 – 4y – y2 = 0 is y = -2 + 2 (2). Solution: -y² - 4y + 4 = 0; y = -(-4) ± ((-4)² - 4(4)(-1)) / 2(-1); y = 4 ± (32)/-2; y = 4 ± 4 (2) /-2; y = 4 + 4 (2) / -2; y = -2 + 2 (2).
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Expert answered|emdjay23|Points 160009|
Question|Asked by baichu
Asked 2/18/2019 2:49:17 PM
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