What is the midpoint of a segment whose endpoints are (4, 0) and (0, -2)? A. (2, -1) B. (4, 2) C. (2, -4) D. (1, -2)

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Asked 8/10/2011 7:15:16 PM

Updated 7/27/2014 8:58:44 PM

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User: What is the midpoint of a segment whose endpoints are (4, 0) and (0, -2)? A. (2, -1) B. (4, 2) C. (2, -4) D. (1, -2)

Weegy:
itolduso|Points 7367|

Question

Asked 8/10/2011 7:15:16 PM

Updated 7/27/2014 8:58:44 PM

1 Answer/Comment

This conversation has been flagged as incorrect.

Flagged by jerry06 [7/27/2014 8:58:44 PM]

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jerry06

The midpoint of a segment whose endpoints are (4, 0) and (0, -2) is (2, -1). M = [(4+0)/2, (0-2)/2]; M = (4/2, -2/2); M = (2, -1)

Added 7/27/2014 8:58:42 PM

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Confirmed by yumdrea [7/28/2014 10:07:54 AM]

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What is the slope of the line that contains the points (8, 3) and (8, –7)?

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Updated 7/31/2014 10:47:22 AM

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jerry06

The slope of the line that contains the points (8, 3) and (8, -7) is undefined. m = (-7-3)/(8-8); m = -10/0

Added 7/31/2014 10:47:22 AM

This answer has been confirmed as correct and helpful.

Confirmed by yumdrea [7/31/2014 10:51:33 AM]

Two angles are _____ if and only if the sum of their measures is 180°.

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Updated 5/31/2014 9:30:23 AM

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andrewpallarca

Two angles are SUPPLEMENTARY if and only if the sum of their measures is 180°.

Added 5/31/2014 9:30:23 AM

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What is the midpoint of a segment whose endpoints are (9, -9) and (-3, 7)?

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Updated 7/27/2014 7:58:40 PM

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jerry06

The midpoint of a segment whose endpoints are (9, -9) and (-3, 7) is (3, -1). M = [(9-3)/2, (-9+7)/2]; M = (6/2, -2/2); M = (3, -1)

Added 7/27/2014 7:58:40 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [7/27/2014 8:01:00 PM]

Two angles are _____ if and only if the sum of their measures is 180°. A. adjacent angles B. vertical angles C. corresponding angles D. supplementary angles

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Updated 5/8/2014 7:24:46 PM

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jerry06

Two angles are supplementary angles if and only if the sum of their measures is 180°.

Added 5/8/2014 7:24:46 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [5/8/2014 7:26:28 PM]

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