Landon is standing in a hole that is 5.1 ft deep. He throws a rock, and it goes up into the air, out of the hole, and then lands on the ground above. The path of the rock can be modeled by the equation y = -0.005x2 + 0.41x - 5.1, where x is the horizontal distance of the rock, in feet, from Landon and y is the height, in feet, of the rock above the ground. How far horizontally from Landon will the rock land?
Question
Updated 7/2/2014 9:12:34 AM
This conversation has been flagged as incorrect.
Flagged by yeswey [7/2/2014 9:12:34 AM]
Original conversation
User: 8x2 + 8x + 2 = 0

User: Landon is standing in a hole that is 5.1 ft deep. He throws a rock, and it goes up into the air, out of the hole, and then lands on the ground above. The path of the rock can be modeled by the equation y = -0.005x2 + 0.41x - 5.1, where x is the horizontal distance of the rock, in feet, from Landon and y is the height, in feet, of the rock above the ground. How far horizontally from Landon will the rock land?

Weegy: y = -0.005x^2 + 0.41x - 5.1. If y = 0, x = 66.7 or 15.3. The lower numberb will be when the rock goes through ground level on the way up, so the rock will land 66.7 feet away.
rugmaker|Points 3224|

User: c^2-10c=0

Weegy: The solutions of the equation c^2-10c=10 is: D. 0, 10
andrewpallarca|Points 24970|

User: Graph the set of points. Which model is most appropriate for the set? (–2, 10), (–1, 1), (0, –2), (1, 1), (2, 10)

Question
Updated 7/2/2014 9:12:34 AM
This conversation has been flagged as incorrect.
Flagged by yeswey [7/2/2014 9:12:34 AM]
Rating
3
8x^2 + 8x + 2 = 0
divided by 2 on both sides the result is:
4x^2 + 4x + 1 = 0
(2x + 1)^2 = 0
2x + 1 = 0
x = -1/2
Confirmed by andrewpallarca [7/2/2014 9:21:24 AM]

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