A 1 mol gas compressed from 8 L to 2 L at constant temperature 300 K. Find work done.

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n = 1 mol T = 300 K V1 = 8 L V2 = 2 L R = 8.314 J/molK Work W = nRT ln(V2/V1) V2/V1 = 2/8 = 0.25 ln(0.25) = -1.3863 W = 1 × 8.314 × 300 × (-1.3863) = -3457 J Answer: -3457 J

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Asked 33 days ago|3/10/2026 9:51:50 AM

Updated 28 days ago|3/14/2026 10:53:06 PM

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Followed by Collins@2012

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cruz30

n = 1 mol
T = 300 K
V1 = 8 L
V2 = 2 L
R = 8.314 J/molK
Work W = nRT ln(V2/V1)
V2/V1 = 2/8
= 0.25
ln(0.25) = -1.3863
W = 1 × 8.314 × 300 × (-1.3863)
= -3457 J
Answer: -3457 J

Added 33 days ago|3/10/2026 10:13:25 AM

This answer has been confirmed as correct and helpful.

Salas1987

W = -(1 mol)(8.314 J/(mol·K))(300 K) ln(2 L / 8 L) = -2494.2 J * ln(0.25) = -2494.2 J * (-1.386) = 3457.8 J.
Therefore, the work done on the gas is 3457.8 J.

Added 33 days ago|3/10/2026 11:24:15 AM

Collins@2012

[Deleted]

Added 28 days ago|3/14/2026 10:53:06 PM

Deleted by MrG [3/14/2026 11:00:49 PM]

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