Question and answer
factor c2 + 6c + 9 completely
c^2 + 6c + 9 = (c + 3)^2
Question
Asked 5/5/2014 10:28:52 AM
Updated 5/6/2014 12:50:30 AM
1 Answer/Comment
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c^2 + 6c + 9 = (c + 3)^2
Added 5/6/2014 12:50:30 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [5/6/2014 12:55:04 AM]
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Questions asked by the same visitor
factor 25a2 - 70a + 49 completely
Weegy: 25a^2 - 70a + 49 (5a - 7)*(5a - 7) or (5a - 7)^2 User: factor 4x2+ 8xy - 60y2 completely Weegy: 4x^2+ 8xy - 60y^2 4(x^2 + 2xy - 15y) 4(x + 5y)(x - 3y) (More)
Question
Expert Answered
Updated 5/6/2014 2:11:07 AM
5 Answers/Comments
Please edit my answer for first question. I wrote 'c' instead of 'a'.
Added 5/5/2014 10:13:03 AM
For the second question you also missed the power of y.
I am wondering if such answers need to be flagged.
Added 5/6/2014 1:07:07 AM
yeswey, can you show us if the missing symbol is within the solution or the final answer?
Added 5/6/2014 1:15:54 AM
The final answer is correct but in the second step he missed the power of y. I will post the answer again.
Added 5/6/2014 2:10:11 AM
4x^2+ 8xy - 60y^2
= 4(x^2 + 2xy - 15y^2)
= 4(x + 5y)(x - 3y)
Added 5/6/2014 2:11:07 AM
factor x2 - 2x - 24 completely
Weegy: x(x+2)-y(x+2)= (x-y)(x+2) User: factor y2 - xy - 56x2 (More)
Question
Updated 5/6/2014 1:04:33 AM
1 Answer/Comment
x^2 - 2x - 24 = (x + 4)(x - 6)
Added 5/6/2014 1:04:33 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [5/6/2014 1:17:16 AM]
factor 25a2 +9b2 + 30ab completely
Weegy: Factor of 25a2+9b2+30ab is (5 a+3 b)^2 User: factor a2 - 9a + 20 completely Weegy: a^2 - a - 20, the factors are (a-5)(a+4) User: factor 5c2 +30c + 45 completely (More)
Question
Updated 5/6/2014 1:02:45 AM
2 Answers/Comments
a^2 - 9a + 20 = (a - 4)(a - 5)
Added 5/6/2014 1:01:44 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [5/6/2014 1:03:37 AM]
5c^2 +30c + 45
= 5(c^2 + 6c + 9)
= 5(c + 3)^2
Added 5/6/2014 1:02:45 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [5/6/2014 1:03:38 AM]
factor 16ax + 4x2 +16a2 completely
Weegy: Factor out the common factor and rearrange in standard form: 4 (x^2 + 4ax + 4a^2) Factor what remains in parentheses: 4 (x + 2a)^2 User: factor 13y2 - 5yx - 8x2 completely (More)
Question
Not Answered
Updated 5/6/2014 1:00:45 AM
1 Answer/Comment
13y^2 - 5yx - 8x^2 = (y - x)(13y + 8x)
Added 5/6/2014 1:00:45 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [5/6/2014 1:03:49 AM]
factor 3y4 - 2y2 - 5 completely
Weegy: Well, first you have to get a common denominator in your fractions. [ So, your equation becomes: 3y/4 - 4y/4 = 5 Then, we do the subtraction: -y/4 = 5 Then, let's get rid of the denominator by multiplying both sides by 4: -y = 20 Which becomes: y = -20 Unless you've typed something wrong, as far as I can tell, the answer is -20. ] User: factor 3y2 +7y + 4 completely Weegy: The factors of 3y^2 +7y + 4 are: (3y + 4)(y + 1) User: factor 450a2 +242c2 + 660ac completely Weegy: First they are all even so we know we can factor out at least a two and we also need tp rearrange to get in the proper sequence. [ so 2(2225a^2 +121c^2 +330ac) Now changing around 2(225a^2 + 330ac + 121 c^2) The portion inside the parentheses is a perfect square so the final answer is 2(15a+11c)^2 ] User: factor 2a2 + 2b2 - 5ab completely Weegy: 2a^2 + 2b^2 - 5ab, when factored is: (a-2b)(2a-b) User: factor 128x2 +96xy + 18y2 completely Weegy: (128 2) (96 x y) (18 y^2) = 442368 x y^3 User: factor y2x - yx - 20 completely (More)
Question
Updated 5/5/2014 7:52:18 PM
2 Answers/Comments
3y^4 - 2y^2 - 5 = (y^2 + 1)(3y^2 - 5)
Added 5/5/2014 7:49:09 PM
This answer has been confirmed as correct and helpful.
Confirmed by alfred123 [5/5/2014 7:55:37 PM]
128x^2 +96xy + 18y^2
= 2(64x^2 + 48xy + 9y^2)
= 2(8x + 3y)(8x + 3y)
= 2(8x + 3y)^2
Added 5/5/2014 7:52:18 PM
This answer has been confirmed as correct and helpful.
Confirmed by alfred123 [5/5/2014 7:55:39 PM]
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