factor c2 + 6c + 9 completely

c^2 + 6c + 9 = (c + 3)^2

Question

Asked 5/5/2014 10:28:52 AM

Updated 5/6/2014 12:50:30 AM

1 Answer/Comment

Rating

3

c^2 + 6c + 9 = (c + 3)^2

Added 5/6/2014 12:50:30 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [5/6/2014 12:55:04 AM]

factor 25a2 - 70a + 49 completely **Weegy:** 25a^2 - 70a + 49
(5a - 7)*(5a - 7)
or (5a - 7)^2
**User:** factor 4x2+ 8xy - 60y2 completely **Weegy:** 4x^2+ 8xy - 60y^2
4(x^2 + 2xy - 15y)
4(x + 5y)(x - 3y)
(More)

Question

Expert Answered

Updated 5/6/2014 2:11:07 AM

5 Answers/Comments

Please edit my answer for first question. I wrote 'c' instead of 'a'.

Added 5/5/2014 10:13:03 AM

For the second question you also missed the power of y.

I am wondering if such answers need to be flagged.

I am wondering if such answers need to be flagged.

Added 5/6/2014 1:07:07 AM

yeswey, can you show us if the missing symbol is within the solution or the final answer?

Added 5/6/2014 1:15:54 AM

The final answer is correct but in the second step he missed the power of y. I will post the answer again.

Added 5/6/2014 2:10:11 AM

factor x2 - 2x - 24 completely

Question

Updated 5/6/2014 1:04:33 AM

1 Answer/Comment

x^2 - 2x - 24 = (x + 4)(x - 6)

Added 5/6/2014 1:04:33 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [5/6/2014 1:17:16 AM]

factor 25a2 +9b2 + 30ab completely **Weegy:** Factor of 25a2+9b2+30ab is
(5 a+3 b)^2 **User:** factor a2 - 9a + 20 completely **Weegy:** a^2 - a - 20, the factors are (a-5)(a+4) **User:** factor 5c2 +30c + 45 completely (More)

Question

Updated 5/6/2014 1:02:45 AM

2 Answers/Comments

a^2 - 9a + 20 = (a - 4)(a - 5)

Added 5/6/2014 1:01:44 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [5/6/2014 1:03:37 AM]

5c^2 +30c + 45

= 5(c^2 + 6c + 9)

= 5(c + 3)^2

= 5(c^2 + 6c + 9)

= 5(c + 3)^2

Added 5/6/2014 1:02:45 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [5/6/2014 1:03:38 AM]

factor 16ax + 4x2 +16a2 completely **Weegy:** Factor out the common factor and rearrange in standard form:
4 (x^2 + 4ax + 4a^2)
Factor what remains in parentheses:
4 (x + 2a)^2 **User:** factor 13y2 - 5yx - 8x2 completely (More)

Question

Not Answered

Updated 5/6/2014 1:00:45 AM

1 Answer/Comment

13y^2 - 5yx - 8x^2 = (y - x)(13y + 8x)

Added 5/6/2014 1:00:45 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [5/6/2014 1:03:49 AM]

factor 3y4 - 2y2 - 5 completely **Weegy:** Well, first you have to get a common denominator in your fractions. [ So, your equation becomes:
3y/4 - 4y/4 = 5
Then, we do the subtraction:
-y/4 = 5
Then, let's get rid of the denominator by multiplying both sides by 4:
-y = 20
Which becomes:
y = -20
Unless you've typed something wrong, as far as I can tell, the answer is -20. ] **User:** factor 3y2 +7y + 4 completely **Weegy:** The factors of 3y^2 +7y + 4 are: (3y + 4)(y + 1) **User:** factor 450a2 +242c2 + 660ac completely **Weegy:**
First they are all even so we know we can factor out at least a two and we also need tp rearrange to get in the proper sequence. [ so
2(2225a^2 +121c^2 +330ac) Now changing around
2(225a^2 + 330ac + 121 c^2) The portion inside the parentheses
is a perfect square so the final answer is
2(15a+11c)^2 ] **User:** factor 2a2 + 2b2 - 5ab completely **Weegy:** 2a^2 + 2b^2 - 5ab, when factored is: (a-2b)(2a-b) **User:** factor 128x2 +96xy + 18y2 completely **Weegy:** (128 2) (96 x y) (18 y^2)
= 442368 x y^3 **User:** factor y2x - yx - 20 completely (More)

Question

Updated 5/5/2014 7:52:18 PM

2 Answers/Comments

3y^4 - 2y^2 - 5 = (y^2 + 1)(3y^2 - 5)

Added 5/5/2014 7:49:09 PM

This answer has been confirmed as correct and helpful.

Confirmed by alfred123 [5/5/2014 7:55:37 PM]

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