Find the quotient. (x 2 - 4xy) ÷ x -x - 4y -x + 4y x

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Find the quotient. (x 2 - 4xy) ÷ x -x - 4y -x + 4y x - 4y

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Asked 6/24/2015 9:33:45 AM

Updated 6/26/2015 5:48:13 PM

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This answer has been confirmed as correct and helpful.

Edited by jeifunk [6/26/2015 5:48:11 PM], Confirmed by jeifunk [6/26/2015 5:48:13 PM]

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Original conversation

User: Find the quotient. (x 2 - 4xy) ÷ x -x - 4y -x + 4y x - 4y

Weegy: (x^2 - 4xy) / x = x - 4y

User: Find the quotient. (5x - 35y + 50) ÷ 5 x - 7y - 10 - x - 7y + 10 x - 7y + 10

Weegy: (5x - 35y + 50) / 5 = x-7 y+10.
emdjay23|Points 46068|

User: Simplify (8z - 10) ÷ (-2) + 5(z - 1). z z - 1 z - 2

Weegy: (8z - 10) / (-2) + 5(z - 1)
= -4z + 5 + 5z - 5
= z

User: Simplify the following expression in your notebook. Select the correct answer. 7 - 3[(n 3 + 8n) ÷ (-n) + 9n 2] -24n2 + 31 n3 - 24n2 + 31 9n2 - 24n + 7 21n + 31

Weegy: 7 - 3[(n3 + 8n) / (-n) + 9n2] = -24n2+ 31
jeifunk|Points 52337|

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Asked 6/24/2015 9:33:45 AM

Updated 6/26/2015 5:48:13 PM

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This answer has been confirmed as correct and helpful.

Edited by jeifunk [6/26/2015 5:48:11 PM], Confirmed by jeifunk [6/26/2015 5:48:13 PM]

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Simplify b(a + b) - a(a - b). a2 + 2ab + b2 a2 - 2ab + b2 -a2 + 2ab + b2 -a2 - 2ab - b2

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Question

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Updated 6/25/2015 11:42:27 PM

1 Answer/Comment

janezeshun

(6z^2 - 4z + 1)(8 - 3z)
= 48z^2 - 32z + 8 - 18z^3 + 12z^2 - 3z
= -18z^3 + 60z^2 - 35z + 8

Added 6/25/2015 10:10:01 PM

This answer has been confirmed as correct and helpful.

Confirmed by Andrew. [6/25/2015 11:45:48 PM]

Multiply (6z 2 - 4z + 1)(8 - 3z). 18z3 - 60z2 + 35z - 8 48z2 - 18z + 8 6z2 - 7z + 9 -18z3 + 60z2 - 35z + 8

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Question

Not Answered

Updated 6/26/2015 10:02:18 AM

2 Answers/Comments

janezeshun

(y^3 - 125) ÷ (y - 5)
= (y^2 + 5y + 25)*(y - 5)/(y - 5)
= y^2 + 5y + 25

Added 6/26/2015 12:06:06 AM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [6/26/2015 10:02:16 AM]

jeifunk

48a^3bc^2 / (3abc)
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Added 6/26/2015 10:01:29 AM

This answer has been confirmed as correct and helpful.

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1 Answer/Comment

yeswey

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Added 7/7/2015 12:37:09 AM

This answer has been confirmed as correct and helpful.

Confirmed by Andrew. [7/7/2015 1:41:30 AM]

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