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Product. (x 2 + 4x + 8)(2x - 1)
Question
Asked 5/1/2015 11:10:21 AM
Updated 5/2/2015 3:11:22 AM
1 Answer/Comment
Flagged by janezeshun [5/2/2015 2:42:32 AM], Edited by yumdrea [5/2/2015 3:11:22 AM]
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User: Product. (x 2 + 4x + 8)(2x - 1)

Question
Asked 5/1/2015 11:10:21 AM
Updated 5/2/2015 3:11:22 AM
1 Answer/Comment
Flagged by janezeshun [5/2/2015 2:42:32 AM], Edited by yumdrea [5/2/2015 3:11:22 AM]
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(x^2 + 4x + 8)(2x - 1)
= 2x^3 + 8x^2 + 16x - x^2 - 4x - 8
= 2x^3 + 7x^2 + 12x - 8
Added 5/2/2015 2:43:19 AM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [5/2/2015 3:11:14 AM]
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Questions asked by the same visitor
Subtract 8x - 8y + 9 from 5x - 8y -z
Question
Updated 4/24/2015 11:19:10 AM
1 Answer/Comment
(5x - 8y -z) - (8x - 8y + 9)
= 5x - 8y -z - 8x + 8y - 9
= -3x - z - 9
Added 4/24/2015 11:19:10 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/24/2015 11:22:45 AM]
Simplify 8 + 3{x - 2[x + 5(x + 3)]}.
Question
Not Answered
Updated 4/24/2015 7:00:12 PM
1 Answer/Comment
8 + 3{x - 2[x + 5(x + 3)]}
= 8 + 3{x - 2(x + 5x + 15)}
= 8 + 3{x - 2(6x + 15)}
= 8 + 3(-11x - 30)
= 8 - 33x - 90
= -33x - 82
Added 4/24/2015 7:00:12 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/25/2015 10:16:35 AM]
(y + z)3
Question
Updated 4/25/2015 5:39:19 AM
1 Answer/Comment
(y + z)3
= (y + z)*(y + z)(y + z)
= (y^2 + 2yz + z^2)(y + z)
= (y^3 + 2y^2z + yz^2 + y^2z + 2yz^2 + z^3)
= y^3 + 3y^2z + 3yz^2 + z^3
Added 4/25/2015 2:59:59 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/25/2015 5:39:13 AM]
Factor this expression mn - 4m - 5n + 20
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Not Answered
Updated 5/1/2015 11:15:24 AM
1 Answer/Comment
mn - 4m - 5n + 20 = (m-5) (n-4)
Added 5/1/2015 11:15:24 AM
This answer has been confirmed as correct and helpful.
find the product of (6 - d)(d 2 - 5 + 3d)
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Not Answered
Updated 5/1/2015 11:24:46 AM
1 Answer/Comment
(6 - d) * (d^2 - 5 + 3d)

= 6d^2 - 30 + 18d - d^3 + 5d - 3d^2;

= -d^3 + 3d^2 + 23d - 30
Added 5/1/2015 11:24:46 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [5/1/2015 11:31:52 AM]
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