Torque on shaft transmitting 5 kW at 100 rpm.

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Angular velocity: w = 2 × n / 60 = 2n × 100 / 60 = 10.47 rad/s Torque: = P / w = 5000 / 10.47 = 477 N·m

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Asked 30 days ago|1/14/2026 12:38:24 PM

Updated 30 days ago|1/14/2026 1:13:20 PM

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cruz30

Angular velocity: w = 2 × n / 60 = 2n × 100 / 60 = 10.47 rad/s
Torque: = P / w = 5000 / 10.47 = 477 N·m

Added 30 days ago|1/14/2026 1:12:41 PM

This answer has been confirmed as correct and helpful.

Flora1988

Torque = (Power * 60) / (2 * * RPM) = (5000 * 60) / (2 * * 100) 477.5 Nm

Added 30 days ago|1/14/2026 1:12:57 PM

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Flora1988

Torque = (Power * 60) / (2 * * RPM) = (5000 * 60) / (2 * * 100) = 477.5 Nm

Added 30 days ago|1/14/2026 1:13:20 PM

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