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A pipeline of radius 5 cm carries water at velocity 2.4 m/s. Determine flow rate.
Q = n r² v r = 0.05 m v = 2.4 m/s r² = 0.05² = 0.0025 Q = 3.1416 × 0.0025 × 2.4 Q = 0.01885 m³/s
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Asked 33 days ago|3/10/2026 11:46:11 AM
Updated 33 days ago|3/10/2026 12:17:16 PM
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A pipeline of radius 5 cm carries water at velocity 2.4 m/s. Determine flow rate.
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cruz30
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Added 33 days ago|3/10/2026 12:17:00 PM
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cruz30
[3/10/2026 12:17:02 PM]
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cruz30
Q = n r² v
r = 0.05 m
v = 2.4 m/s
r² = 0.05² = 0.0025
Q = 3.1416 × 0.0025 × 2.4
Q = 0.01885 m³/s
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Added 33 days ago|3/10/2026 12:17:16 PM
This answer has been confirmed as correct and helpful.
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Questions asked by the same visitor
A turbine produces 2.5 MW with efficiency 0.82. If input fuel power = P, find P.
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Question
Not Answered
Updated 34 days ago|3/9/2026 8:30:01 AM
1 Answer/Comment
3
cruz30
Determine input fuel power.
Pout = × Pin
Pout = 2.5 MW
= 0.82
Pin = Pout / n
Pin = 2.5 / 0.82
Pin = 3.05 MW
Added 34 days ago|3/9/2026 8:30:01 AM
This answer has been confirmed as correct and helpful.
A spacecraft travels 3.2×10 km in 4.5 hours. Determine average velocity in m/s.
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Question
Not Answered
Updated 34 days ago|3/9/2026 8:29:43 AM
1 Answer/Comment
3
cruz30
Determine average velocity of spacecraft.
Distance = 3.2×10 km = 3.2×10 m
Time = 4.5 h = 4.5 × 3600 = 16,200 s
v = d / t
v = 3.2×10 / 16,200
v = 19,753 m/s
Added 34 days ago|3/9/2026 8:29:43 AM
This answer has been confirmed as correct and helpful.
A cylindrical tank radius 2.4 m, height 5.6 m. Determine volume.
Weegy:
V = n *r^2*h = n*1.5^2*4 = n *2.25*4 = 9*n = 28.27 m?
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Question
Updated 34 days ago|3/9/2026 8:57:27 AM
1 Answer/Comment
3
cruz30
Given
r=2.4 m
h=5.6 m
V=nr^2h
=n(2.4)^2x5.6
=n(5.76)x5.6
=32.256n m^3
Added 34 days ago|3/9/2026 8:57:27 AM
This answer has been confirmed as correct and helpful.
A beam carries 8 kN load at center over span 6 m. Determine bending moment at center.
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Question
Not Answered
Updated 34 days ago|3/9/2026 8:29:19 AM
1 Answer/Comment
3
cruz30
Determine bending moment at center of simply supported beam.
M = (P × L) / 4
P = 8 kN = 8000 N
L = 6 m
M = (8000 × 6) / 4
M = 48,000 / 4
M = 12,000 N·m
Added 34 days ago|3/9/2026 8:29:19 AM
This answer has been confirmed as correct and helpful.
A chemical reactor converts 75% of reactant A. Initial 120 mol. Determine remaining moles.
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Question
Not Answered
Updated 34 days ago|3/9/2026 8:29:01 AM
1 Answer/Comment
3
cruz30
Determine remaining moles of reactant A.
Initial = 120 mol
Conversion = 75% = 0.75
Remaining = 120 × (1 - 0.75)
Remaining = 120 × 0.25
Remaining = 30 mol
Added 34 days ago|3/9/2026 8:29:01 AM
This answer has been confirmed as correct and helpful.
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