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The sum of ten numbers is 2624. If one of the ten numbers is changed from 456 to 654, what is the new sum?
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Question
Asked 2/3/2009 8:01:02 PM
Updated 4/28/2020 2:31:38 PM
1 Answer/Comment
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The sum of ten numbers is 2624. If one of the ten numbers is changed from 456 to 654, what is the new sum?
Original conversation
User:
The sum of ten numbers is 2624. If one of the ten numbers is changed from 456 to 654, what is the new sum?
Weegy:
The new sum will be 2822.Can be got by 2624-456+654.
Expert answered|mythmoh|Points 204|Rating *** (+40 -3)
User:
70% of 40 =
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Question
Asked 2/3/2009 8:01:02 PM
Updated 4/28/2020 2:31:38 PM
1 Answer/Comment
New answers
Rating
8
Sting
M
70*40/100 = 28
70% of 40 = 28
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Added 4/28/2020 2:31:38 PM
This answer has been confirmed as correct and helpful.
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Questions asked by the same visitor
70% of 40=
(More)
Question
Updated 3/16/2014 3:42:02 AM
1 Answer/Comment
8
alfred123
M
70% of 40 = 28
Added 3/16/2014 3:42:02 AM
This answer has been confirmed as correct and helpful.
What is 70 percent of 40?
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Question
Not Answered
Updated 5/29/2015 8:09:13 PM
1 Answer/Comment
8
yumdrea
M
70 percent of 40
= 70% of 40
= .70 * 40
= 28
Added 5/29/2015 8:09:13 PM
This answer has been confirmed as correct and helpful.
three-fifths of ___ =15
Weegy:
Three-fifths of 25 is 15.
(More)
Question
Expert Answered
Updated 3/16/2014 3:40:21 AM
0 Answers/Comments
Corinda has 400 ft. of fencing to make a play area. She wants the fenced area to be rectangular. What dimensions should she use in order to enclose the maximum possible area?
Weegy:
(More)
Question
Expert Answered
Updated 1/31/2024 3:45:13 AM
1 Answer/Comment
3
Bench_14
Solution:
For a rectangular play area, the perimeter (P) is given by the formula P = 2l + 2w, where l is the length and w is the width.
In this case, Corinda has 400 feet of fencing, so 2l + 2w = 400.
Now, solve for l: l = 400 / 4 = 100.
So, the length (l) and width (w) of the rectangular play area should be 100 feet each, forming a square, which maximizes the enclosed area.
Added 1/31/2024 3:45:00 AM
This answer has been confirmed as correct and helpful.
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