Solve for y by using the quadratic formula: y2 - 4y - 21 = 0.
y^2 - 4y - 21 = 0 (y - 7)(y + 3) = 0; y - 7 = 0; y = 7; y + 3 = 0; y = -3; y = {-3, 7}
Updated 3/2/2015 3:14:48 PM
Rating
3
y^2 - 4y - 21 = 0

(y - 7)(y + 3) = 0;

y - 7 = 0; y = 7;
y + 3 = 0; y = -3;

y = {-3, 7}
Confirmed by sujaysen [3/2/2015 3:15:48 PM]

Simplify the following expression. y^2-16/y-4.
Question
Updated 2/26/2015 9:40:48 PM
y^2-16/y-4
= (y + 4)(y - 4)/(y - 4)
= y + 4 where y can not be 4.
Confirmed by Andrew. [2/26/2015 9:44:37 PM]
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