a current phasor I base1 is 5A and horizontal a second phasor I2 is 8A and is at 50 degrees to the horizontal determine the resultant of the two phasors and the angle it makes with the current I base1 using the following methods.

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Asked 11/14/2010 12:13:05 PM

Updated 276 days ago|9/14/2023 5:37:28 AM

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Asked 11/14/2010 12:13:05 PM

Updated 276 days ago|9/14/2023 5:37:28 AM

1 Answer/Comment

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We can also use trigonometry to find the magnitude and angle of the resultant. To do this, we first find the horizontal and vertical components of each phasor using their magnitudes and angles. Using this method, we get:

Horizontal component of I base1 = 5 A Vertical component of I base1 = 0 A

Horizontal component of I2 = 8 A * cos(50) = 5.12 A Vertical component of I2 = 8 A * sin(50) = 6.11 A

Horizontal component of resultant = 5 A + 5.12 A = 10.12 A Vertical component of resultant = 0 A + 6.11 A = 6.11 A

Magnitude of resultant = sqrt((10.12 A)^2 + (6.11 A)^2) 11.9 A Angle of resultant with respect to horizontal axis = arctan(6.11 A / 10.12 A) 30 degrees

Therefore, using either method, we can determine that the magnitude of the resultant is approximately 11.9 A, and its angle with respect to current I base1 is approximately 30 degrees.

Horizontal component of I base1 = 5 A Vertical component of I base1 = 0 A

Horizontal component of I2 = 8 A * cos(50) = 5.12 A Vertical component of I2 = 8 A * sin(50) = 6.11 A

Horizontal component of resultant = 5 A + 5.12 A = 10.12 A Vertical component of resultant = 0 A + 6.11 A = 6.11 A

Magnitude of resultant = sqrt((10.12 A)^2 + (6.11 A)^2) 11.9 A Angle of resultant with respect to horizontal axis = arctan(6.11 A / 10.12 A) 30 degrees

Therefore, using either method, we can determine that the magnitude of the resultant is approximately 11.9 A, and its angle with respect to current I base1 is approximately 30 degrees.

Added 276 days ago|9/14/2023 5:37:04 AM

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