We can also use trigonometry to find the magnitude and angle of the resultant. To do this, we first find the horizontal and vertical components of each phasor using their magnitudes and angles. Using this method, we get:
Horizontal component of I base1 = 5 A Vertical component of I base1 = 0 A
Horizontal component of I2 = 8 A * cos(50) = 5.12 A Vertical component of I2 = 8 A * sin(50) = 6.11 A
Horizontal component of resultant = 5 A + 5.12 A = 10.12 A Vertical component of resultant = 0 A + 6.11 A = 6.11 A
Magnitude of resultant = sqrt((10.12 A)^2 + (6.11 A)^2) 11.9 A Angle of resultant with respect to horizontal axis = arctan(6.11 A / 10.12 A) 30 degrees
Therefore, using either method, we can determine that the magnitude of the resultant is approximately 11.9 A, and its angle with respect to current I base1 is approximately 30 degrees.