8 x 2 + 9 /3

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8 x 2 + 9 /3

8 x 2 + 9/3 = 16 + 9/3 = 16 + 3 = 19

Expert answered|lana1924|Points 5|

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Asked 11/13/2010 12:37:25 AM

Updated 10/31/2014 6:25:07 PM

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Edited by andrewpallarca [10/31/2014 6:25:07 PM], Confirmed by andrewpallarca [10/31/2014 6:25:09 PM]

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Jocelyn has test scores of 75, 83 and 91 on her first three algebra tests. What must she score on her 4th test so she will have at least an 85 average?

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1 Answer/Comment

debnjerry

Jocelyn has test scores of 75, 83 and 91 on her first three algebra tests. To have at least an 85 average, she must score at least 91 on her 4th test.
(75+83+91+x)/4=85
249+x=85*4
249+x=340
x=340-249
x=91

Added 1/9/2016 6:54:40 AM

This answer has been confirmed as correct and helpful.

Solve for x: -2x + 4 >10

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Updated 10/31/2014 6:24:14 PM

1 Answer/Comment

andrewpallarca

-2x + 4 >10;
-2x > 10 - 4;
-2x > 6;
x < 6/-2;
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Added 10/31/2014 6:24:14 PM

This answer has been confirmed as correct and helpful.

Solve by using PEMDAS: 8 x 2 + 9 /3

Weegy: 8 x 2 + 9 /3 = 16 + 9 /3 = 16 + 3 =19 User: Solve by using PEMDAS: 6 + 3^2 * 2 / (5 - 2) Weegy: 6 + 3^2 * 2 / (5 - 2) = 6 + 3^2 * 2 / 3 = 6 + 9 * 2 / 3 = 6 + 18/3 = 6 + 6 = 12 (More)

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Updated 10/31/2014 6:27:07 PM

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Simplify: 3(x + 13)

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