Write the equation of a circle whose center is at the origin and contains the point (2, 3).
Question
Updated 4/30/2014 12:31:02 AM
Flagged by yeswey [4/30/2014 12:29:21 AM]
Original conversation
User: Write the equation of a circle whose center is at the origin and contains the point (2, 3).

Question
Updated 4/30/2014 12:31:02 AM
Flagged by yeswey [4/30/2014 12:29:21 AM]
Rating
3
The equation of a circle whose center is at the origin and contains the point (2, 3) is x^2 + y^2 = r^2 where r is the radius of the circle. Since the point (2, 3) is on the circle, so, 2^2 + 3^2 = r^2 = 13
The equation of the circle is x^2 + y^2 = 13
Confirmed by jeifunk [4/30/2014 12:40:20 AM]

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