Solve the following system of equations.
2x + y = 3
x = 2y - 1

2x + y = 3 x = 2y - 1 substitute x in the first equation the result is: 2(2y - 1) + y = 3 4y - 2 + y = 3 5y = 3 + 2 = 5 y = 5/5 = 1 x = 2(1) - 1 = 2 - 1 = 1 The solution for the system 2x + y = 3 x = 2y - 1 is (1, 1)

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Asked 3/6/2012 1:09:16 PM

Updated 11/19/2014 10:36:08 AM

1 Answer/Comment

Edited by andrewpallarca [11/19/2014 10:36:08 AM]

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2x + y = 3

x = 2y - 1

substitute x in the first equation the result is:

2(2y - 1) + y = 3

4y - 2 + y = 3

5y = 3 + 2 = 5

y = 5/5 = 1

x = 2(1) - 1 = 2 - 1 = 1

The solution for the system 2x + y = 3 x = 2y - 1 is (1, 1)

x = 2y - 1

substitute x in the first equation the result is:

2(2y - 1) + y = 3

4y - 2 + y = 3

5y = 3 + 2 = 5

y = 5/5 = 1

x = 2(1) - 1 = 2 - 1 = 1

The solution for the system 2x + y = 3 x = 2y - 1 is (1, 1)

Added 11/18/2014 11:47:54 PM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [11/19/2014 10:36:01 AM], Rated good by andrewpallarca

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