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Solve the inequality. Show your work. |r + 3| = 7
Inequality of |r + 3| = 7 is r = 4 or r = -10 Solution; Solve for r over the real numbers: abs(r+3) = 7 Eliminate the absolute value. Split the equation into two possible cases: r+3 = 7 or r+3 = -7 Look at the first equation: Solve for [ r. Subtract 3 from both sides: r = 4 or r+3 = -7 Look at the second equation: Solve for r. Subtract 3 from both sides: Answer: | | r = 4 or r = -10 ]
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emdjay23
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Asked 4/6/2013 7:19:28 PM
Updated 7/23/2014 12:16:18 PM
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Solve the inequality. Show your work. |r + 3| = 7
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andrewpallarca
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|r + 3| = 7; r = 4 or r = -10
r + 3 = 7; r = 7 - 3; r = 4;
-(r + 3) = 7; -r - 3 = 7; -r = 7 + 3; -r = 10; r = -10
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Added 7/23/2014 12:16:18 PM
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Simplify the expression. 4 square root 6+5 square root 6
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Updated 1/25/2015 6:40:27 PM
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yeswey
4 square root 6 + 5 square root 6
= 4 sqrt 6 + 5 sqrt 6
= 9 sqrt 6
Added 1/25/2015 6:40:27 PM
This answer has been confirmed as correct and helpful.
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jeifunk
[1/25/2015 10:09:22 PM]
4t + 2u2 – u3; t = 2 and u = 1
Weegy:
4t + 2u^2 – u^3; t = 2 and u = 1: 4(2) + 2(1)^2 - 1^3 = 8 + 2 - 1 = 10 - 1 = 9
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