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Write the equation of a line with slope m = 6 and including point (0, 1).
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Asked 1/5/2013 9:24:09 PM
Updated 1/6/2013 7:14:17 AM
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Flagged by yeswey
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User: Write the equation of a line with slope m = 6 and including point (0, 1).

Question
Asked 1/5/2013 9:24:09 PM
Updated 1/6/2013 7:14:17 AM
1 Answer/Comment
Flagged by yeswey
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Rating
5
The "point-slope" form of the equation of a straight line is:
y - y1 = m(x - x1)
thus y - 1 = 6 (x - 0)
Simplify the equation we get y = 6x + 1
The line with slope m = 6 including point (0, 1) is y = 6x + 1
Added 1/6/2013 7:14:19 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [5/28/2014 1:34:08 AM]
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Questions asked by the same visitor
Find the slope between points (4, 6) and (-2, 6).
Weegy: 0.02777777777 (More)
Question
Updated 1/6/2013 7:31:53 AM
1 Answer/Comment
the slope between points (4, 6) and (-2, 6)
The slope m = (y2-y1)/(x2-x1) = (6-6)/(-2-4) = 0
Note that when a line is horizontal the slope is 0.
Added 1/6/2013 7:31:53 AM
This answer has been confirmed as correct and helpful.
Confirmed by Andrew. [7/22/2016 5:13:14 PM]
Solve the quadratic equation y2 - 5y = -4 by factoring.
Weegy: The answer is "real and irrational root" ; Solution: discriminant of ax^2 + bx + c = 0 is b^2 - 4ac if D = 0 double root D 0 and is a perfect square - - - -real and rational distinct roots D>0 and is not a perfect square - - - -real and irrational [ [ distinct roots here D = 5^2 - 4*1*(-3) = 25 + 12 = 37 not a perfect square so therefore it is a real and irrational root . ] ] (More)
Question
Expert Answered
Updated 1/6/2013 8:28:01 AM
1 Answer/Comment
y^2 - 5y = -4
y^2 - 5y + 4 = 0
(y - 1) (y - 4) = 0
y = 1 or y = 4
Added 1/6/2013 8:28:01 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [5/28/2014 1:34:12 AM]
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