Subtract: (2x2 - 6x + 7) - (5x2 + 2x - 8). A) -3x2 - 8x + 15 B) -3x4 - 8x2 + 15 C) -3x2 - 4x - 1 D) 7x2 - 4x - 1
(2x^2 - 6x + 7) - (5x^2 + 2x - 8) = 2x^2 - 6x + 7 - 5x^2 - 2x + 8 = -3x^2 - 8x + 15
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Asked 9/13/2012 1:13:27 PM
Updated 8/12/2014 11:46:29 PM
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(2x^2 - 6x + 7) - (5x^2 + 2x - 8)
= 2x^2 - 6x + 7 - 5x^2 - 2x + 8
= -3x^2 - 8x + 15
Added 8/12/2014 11:46:29 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [8/12/2014 11:47:17 PM]

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