find all the roots and check your answers. x^2 + 5x - 14 = 0
Question
Updated 223 days ago|7/25/2023 2:14:49 PM
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Original conversation
User: find all the roots and check your answers. x^2 + 5x - 14 = 0

User: find all the roots and check your answers. 3x^2 + 5x = 0

User: find all the roots and check your answers. 49x^2 - 25 = 0

Weegy: Mathematically speaking, the answer would be x = ?5/7 ~~ ?0.71429.

User: find all the roots and check your answers. 4x^2 - 13x + 3 = 0

Question
Updated 223 days ago|7/25/2023 2:14:49 PM
Rating
3
The roots of the quadratic equation 3x^2 + 5x = 0 are x = 0 and x = -5/3.
Added 223 days ago|7/25/2023 2:13:12 PM
This answer has been flagged as incorrect.
Deleted by •|Don [7/25/2023 2:13:19 PM]
3
The roots of the equation 3x^2 + 5x = 0 are: x = 0 and x = -5/3.

Verification:
For x = 0: 3(0)^2 + 5(0) = 0 (True)
For x = -5/3: 3(-5/3)^2 + 5(-5/3) = 0 (True)
Added 223 days ago|7/25/2023 2:13:48 PM
3
The roots of the equation 49x^2 - 25 = 0 are: x = 5/7 and x = -5/7.

Verification:
For x = 5/7: 49(5/7)^2 - 25 = 0 (True)
For x = -5/7: 49(-5/7)^2 - 25 = 0 (True)
Added 223 days ago|7/25/2023 2:14:21 PM
3
The roots of the equation 4x^2 - 13x + 3 = 0 are: x = 1/4 and x = 3.

Verification:
For x = 1/4:
4(1/4)^2 - 13(1/4) + 3 = 0
4/16 - 13/4 + 3 = 0
1/4 - 13/4 + 3 = 0
(1 - 13 + 12)/4 = 0
0 = 0 (True)

For x = 3:
4(3)^2 - 13(3) + 3 = 0
4(9) - 39 + 3 = 0
36 - 39 + 3 = 0
0 = 0 (True)
Added 223 days ago|7/25/2023 2:14:49 PM

Questions asked by the same visitor
Add or substract the follow polynomials as indicated: (5.9x^3 +3.4x^2 - 7) - (2.9x^3 -9.6x^3) - (9.6x^2 + 3)
Weegy: (5.9x^3 +3.4x^2 - 7) - (2.9x^3 -9.6x^3 - 9.6x^2 + 3) = 12.6x^3+13.x^2-10 User: multiply. (6x +7)(3x+2) Weegy: (6x+7)(3x+2) = 18x^2+33x+14 User: Multiply. (4x + 1)(2x^2 + x + 1) Weegy: 5/2x+1/4x=7/4+x SOLUTION: 5/2x+1/4x-x=7/4 >> (5/2+1/4-1)x=7/4 >> (7/4)x=7/4 >> x=(7/4)/(7/4) >> x=1 (More)
Question
Updated 4/30/2015 2:33:25 AM
(4x + 1)(2x^2 + x + 1)
=8x^3+2x^2+4x^2+x+4x+1
=8x^3+6x^2+5x+1
Confirmed by Andrew. [4/30/2015 2:53:40 AM]
Use the difference of two squares forumula to factor. 4x^2 - 25 User: Use the difference of two squares forumula to factor. 81x^2 - 1
Weegy: Solution: 81x^2-1 = (9x)^2-1^2 = (9x+1)(9x-1) ; therefore the answer is (9x+1)(9x-1) . (More)
Question
Updated 4/30/2015 2:52:10 AM
4x^2 - 25

= (2x)^2 - 5^2

= (2x - 5)(2x + 5)
Confirmed by Andrew. [4/30/2015 2:52:19 AM]
38,928,452
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