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what is the solution set for this quadratic formula: x^2 - 3x = -4
x^2 - 3x = -4 x^2 - 3x + 4 = 0 a = 1, b = -3, c = 4 discriminant = b^2 - 4ac = (-3)^2 - 4(1)(4) = 9 - 16 = -7 < 0 There are no real roots for the equation x^2 - 3x = -4 Two complex roots are x = [3 ± sqrt (-7)]/2 = [3 ± (sqrt 7)i]/2
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Asked 3/21/2012 2:34:47 PM
Updated 1/27/2015 11:58:54 PM
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x^2 - 3x = -4
x^2 - 3x + 4 = 0
a = 1, b = -3, c = 4
discriminant = b^2 - 4ac = (-3)^2 - 4(1)(4) = 9 - 16 = -7 < 0
There are no real roots for the equation x^2 - 3x = -4
Two complex roots are x = [3 ± sqrt (-7)]/2 = [3 ± (sqrt 7)i]/2
Added 1/27/2015 11:58:54 PM
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