**Weegy:** length 22 feet , width 11 feet

**User:** show work please

**Weegy:** Please give me the equation

**User:** The length of rectangle is 4 feet less than twice its width.
Find the dimensions if the perimeter is 100 feet.

**Weegy:** length 22 feet , width 11 feet

**User:** can you show your work

**User:** what

**Weegy:** I am waiting for a question from you. How can I help you.

**User:** The length of rectangle is 4 feet less than twice its width.
Find the dimensions if the perimeter is 100 feet. with work not just the answer

**Weegy:** L= Length
W= Width
P= Perimeter
Equation 1: L= 2W-4
Equation 2: 2L+2W=P=100
Then,
From Equation 2,
Solve the second equation for 2W.
2L + 2W= 100
2W = 100 - 2L
From Equation 1,
Substitute 100-2L for 2W in the first [ equation. This gives the equation one variable, which earlier algebra work.
L=(100-2L)-4
L=100-2L-4
2L + L= 100- 4
3L= 96
L=32
Now, substitute 32 for L in either equation and solve for w.
From Equation 1
32 = 2W - 4
4 +32 = 2W
36 = 2W
36 / 2 =W
16=W
answer L=32 and W=16
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