(12y3 + 9 y2 + 21y) ÷ 3y
Question
Updated 3/18/2015 7:04:18 AM
This conversation has been flagged as incorrect.
Flagged by janezeshun [3/18/2015 7:00:32 AM]
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Original conversation
User: (12y3 + 9 y2 + 21y) ÷ 3y

Weegy: x+3y=-15 3y=-x-15 y=(-1/3)x-5
user1583|Points 1061|

User: (10x2 – 14x – 12) ÷ (5x + 3)

Weegy: x=-2 or-2x
jhun009|Points 15|

User: (8x – 2) + (7x + 6)

Weegy: The answer is 15x = -1 or x = -1/15
dexterity|Points 120|

User: (4x – 3.5) – (3x + 1.7)

User: (5x – 5 ) – ( 3x – 3)

Weegy: is equal to 8x
beboythewizkid|Points 1608|

User: Find the product of (x2 - 3x + 2) with the quotient of (6x6 - 9x5 - 3x3) ÷ 3x3.

Weegy: (x^2-3x+2)(x^3+x^2+x+1) x^5-2x^4-x^3+3x^2-3x-2

Question
Updated 3/18/2015 7:04:18 AM
This conversation has been flagged as incorrect.
Flagged by janezeshun [3/18/2015 7:00:32 AM]
Rating
8
(12y^3 + 9y2 + 21y) ÷ 3y
= 4y^2 + 3y + 7
8
(10x^2 – 14x – 12) ÷ (5x + 3)
= (5x + 3)(2x - 4)/(5x + 3)
= 2x - 4
8
(8x – 2) + (7x + 6)
= 8x + 7x - 2 + 6
= 15x + 4
8
(4x – 3.5) – (3x + 1.7)
= 4x - 3.5 - 3x - 1.7
= x - 5.2
Confirmed by yumdrea [3/19/2015 2:26:09 AM]
8
(5x – 5 ) – ( 3x – 3)
= 5x - 5 - 3x + 3
= 2x - 2
Confirmed by yumdrea [3/19/2015 2:26:59 AM]
8
the product of (x2 - 3x + 2) with the quotient of (6x6 - 9x5 - 3x3) ÷ 3x3 is
(x^2 - 3x + 2){(6x^6 - 9x^5 - 3x^3)/3x^3}
= (x^2 - 3x + 2){2x^3 - 3x^2 - 1}
= 2x^5 - 6x^4 + 4x^3 - 3x^4 + 9^3 - 6x^2 - x^2 + 3x - 2
= 2x^5 - 9x^4 +13x^3 - 7x^2 + 3x - 2

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