From a deck of 52 cards, probability that all 4 aces are drawn before any king

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Consider only 8 cards: 4 aces (A) and 4 kings (K) Total orderings = 8! / (4!×4!) = 70 Favorable: all Aces before any King only 1 way (AAAAKKKK) Probability = 1 / 70

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Asked 106 days ago|2/23/2026 9:24:48 AM

Updated 106 days ago|2/23/2026 9:55:49 AM

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cruz30

Consider only 8 cards: 4 aces (A) and 4 kings (K)
Total orderings = 8! / (4!×4!) = 70
Favorable: all Aces before any King only 1 way (AAAAKKKK)
Probability = 1 / 70

Added 106 days ago|2/23/2026 9:55:25 AM

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Salas1987

P(AAAA before KKKK) = (4/8) * (3/7) * (2/6) * (1/5)
= (1/2) * (3/7) * (1/3) * (1/5)
= (1 * 3 * 1 * 1) / (2 * 7 * 3 * 5)
= 3 / 210
= 1 / 70.
The probability that all 4 aces are drawn before any king is 1/70

Added 106 days ago|2/23/2026 9:55:49 AM

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Updated 106 days ago|2/23/2026 8:15:08 AM

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Updated 106 days ago|2/23/2026 8:12:48 AM

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Updated 106 days ago|2/23/2026 8:12:11 AM

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Updated 106 days ago|2/23/2026 8:11:30 AM

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Added 106 days ago|2/23/2026 8:11:30 AM

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