The line that passes through (-1, -3) and (2, 1) is y=4/3x-5/3. Assuming that y=ax+b, put the two points into the equation, -3=-a+b, 1=2a+b. 1+3=2a+a 4=3a a=4/3, b=1-2a =1-2x4/3 =1-8/3 =3/3-8/3 =-5/3. So y=4/3x-5/3.

The slope of the line that passes through the points (2, 1) and (-1, -1) is 2/3. Assuming that y=ax+b, put two points into it 1=2a+b.-1=-a+b 2=3a a=2/3. b=-1+a b=-1+2/3 b=-1/3. y=2/3x-1/3. 2/3 is the slope.

Weegy: 2 (5) = 5 (7) + 7 User: The slope of the line whose equation is 2x + 5y + 1 = 0 is Weegy: To find the slope of this line, put the equation into SLOPE INTERCEPT FORM: y=mx+b. This is the easiest method for solving this type of problem, because the 'm' in slope-intercept form equals your slope. [ To put it in this form, isolate y.
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